Of the 12 temporary employees in a certain company, 4 will be hired as permanent employees. If 5 of the 12 temporary employees are women, how many of the possible groups of 4 employees consist of 3 women and one man?
A. 22
B. 35
C. 56
D. 70
E. 105
Since 5 of the 12 temporary employees are women, 7 are men.
Number of ways to choose 1 man from 7 options = 7C1 = 7.
Number of ways to choose 3 women from 5 options = 5C3 = (5*4*3)/(3*2*1) = 10.
To combine the options above, we multiply:
7*10 = 70.
The correct answer is
D.
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