I presume this will be easy to most of the "solving" people here

How many 4 digit positive integers do not contain the digit 3 or 6?

1. 2401

2. 3584

3. 4096

4. 5040

5. 7200

## Digits, Numbers

##### This topic has expert replies

### GMAT/MBA Expert

- Brent@GMATPrepNow
- GMAT Instructor
**Posts:**13576**Joined:**08 Dec 2008**Location:**Vancouver, BC**Thanked**: 5254 times**Followed by:**1256 members**GMAT Score:**770

Take the task of building 4-digit positive integers and break it into stages.vinay1983 wrote:I presume this will be easy to most of the "solving" people here

How many 4-digit positive integers do not contain the digit 3 or 6?

A. 2401

B. 3584

C. 4096

D. 5040

E. 7200

Stage 1: Choose a thousands digit

This can be 1,2,4,5,7,8,or 9, so we can complete stage 1 in 7 ways

Stage 2: Choose a hundreds digit

This can be 0,1,2,4,5,7,8,or 9, so we can complete stage 2 in 8 ways

Stage 3: Choose a tens digit

This can be 0,1,2,4,5,7,8,or 9, so we can complete stage 3 in 8 ways

Stage 4: Choose a units digit

This can be 0,1,2,4,5,7,8,or 9, so we can complete stage 4 in 8 ways

By the Fundamental Counting Principle (FCP) we can complete all 4 stages (and thus build a 4-digit positive integer) in (7)(8)(8)(8) ways

IMPORTANT: we don't really need to calculate the product (7)(8)(8)(8)

We can just recognize that the units digit will be 4. That is (7)(8)(8)(8) = ---4

Since answer choice B, is the only one with units digit 4, it must be correct.

Cheers,

Brent

**Aside**: For more information about the FCP, watch our free video: https://www.gmatprepnow.com/module/gmat-counting?id=775

Brent Hanneson - Creator of GMATPrepNow.com

Use my video course along with

Sign up for

And check out all of these

Use my video course along with

**Beat The GMAT's free 60-Day Study Guide**Sign up for

**free Question of the Day**emailsAnd check out all of these

**free resources**-
- Master | Next Rank: 500 Posts
**Posts:**391**Joined:**02 Mar 2013**Thanked**: 50 times**Followed by:**4 members

We have 4 places to fill to make 4 digit number ----vinay1983 wrote:I presume this will be easy to most of the "solving" people here

How many 4 digit positive integers do not contain the digit 3 or 6?

1. 2401

2. 3584

3. 4096

4. 5040

5. 7200

Now for the thousands digit we have only 7 options( we can't use 0,3 and 6).

For hundred tens and units digit we can use 8 digit( because we can't use 3 or 6 but we can use 0).

So the total number of 4 digit numbers without 3 or 6 is 7*8*8*8=3584

Answer is B

### GMAT/MBA Expert

- Jay@ManhattanReview
- GMAT Instructor
**Posts:**2512**Joined:**22 Aug 2016**Location:**Grand Central / New York**Thanked**: 470 times**Followed by:**32 members

Do you mean to ask, "How many 4 digit positive integers do not contain the digit 3 AND 6 together (not necessarily in order)?"Zoser wrote:What would the answer be if the question said 3 AND 6 instead of 3 or 6?

If yes, then let's follow this.

# of 4 digit positive integers do not contain the digit 3 AND 6 together = Total # of 4 digit positive integers - Total # of 4 digit positive integers that contain the digit 3 AND 6 together

Total # of 4 digit positive integers = 9*10*10*10 = 9(10^3) = 9000

"Total # of 4 digit positive integers that contain the digit 3 AND 6 together" can be computed the following way.

A. For '3' appears before '6':

a. Say '3' is in the thousands place and '6' in the hundreds place.

3 6 _ _ : 1*1*10*10 = 100

b. Say '3' is in the thousands place and '6' in the tens place.

3 _ 6 _ : 1*10*1*10 = 100

c. Say '3' is in the thousands place and '6' in the unit place.

3 _ _ 6 : 1*10*10*1 = 100

-----------------------

d. Say '3' is in the hundreds place and '6' in the tens place.

_3 6 _ : 9*1*1*10 = 90

e. Say '3' is in the hundreds place and '6' in the unit place.

_3 _ 6 : 9*1*10*1 = 90

------------------------

f. Say '3' is in the tens place and '6' in the unit place.

_ _3 6 : 9*10*1*1 = 90

-------------------------

Total # in which '3' appears before '6' = 100 + 100+ 100 + 90 + 90 + 90 = 570;

Similarly, total # in which '6' appears before '3' = 570;

Total # of 4 digit positive integers that contain the digit 3 AND 6 together = 570 + 570 = 1140

Thus, # of 4 digit positive integers do not contain the digit 3 AND 6 together = 9000 - 1140 = 7860.

Hope this is clear.

Relevant book: Manhattan Review GMAT Number Properties Guide

-Jay

_________________

Manhattan Review GMAT Prep

Locations: New York | Singapore | London | Dubai | and many more...

Schedule your free consultation with an experienced GMAT Prep Advisor! Click here.

### GMAT/MBA Expert

- ceilidh.erickson
- GMAT Instructor
**Posts:**2094**Joined:**04 Dec 2012**Thanked**: 1443 times**Followed by:**240 members

Jay gave a good explanation, but... you're never actually going to see a question like this on the GMAT.Zoser wrote:What would the answer be if the question said 3 AND 6 instead of 3 or 6?

Questions that have vague or confusing wording are open to multiple interpretations, and as a result, they will yield bad data. Some high-scorers will get them wrong while low-scorers get them right, so it won't be a good indicator of ability level. Questions like this would be thrown out after experimentation (remember that a certain percentage of all questions that you'll see will be experimental). Since there's ambiguity about what "and" would mean in this context, it's not a question you'd see on the real test.

Broadly speaking, the combinatorics question that you're likely to see on the real GMAT are more straightforward and less tricky than a lot of the ones floating out there on the internet (including on this forum).

Ceilidh Erickson

Manhattan Prep GMAT & GRE instructor

EdM in Mind, Brain, and Education

Harvard Graduate School of Education

Manhattan Prep instructors all have 99th+ percentile scores and expert teaching experience.

Sign up for a FREE TRIAL, and learn why we have the highest ratings in the GMAT industry!

### GMAT/MBA Expert

- Scott@TargetTestPrep
- GMAT Instructor
**Posts:**4190**Joined:**25 Apr 2015**Location:**Los Angeles, CA**Thanked**: 43 times**Followed by:**21 members

We need to determine how many 4-digit positive integers do not contain a 3 or a 6.vinay1983 wrote:I presume this will be easy to most of the "solving" people here

How many 4 digit positive integers do not contain the digit 3 or 6?

1. 2401

2. 3584

3. 4096

4. 5040

5. 7200

For the first digit (the thousands digit), we have the options of 1, 2, 4, 5, 7, 8, and 9, so there are 7 options. For the next digit (the hundreds digit), we have 8 options, since we can include 0. For the next digit (the tens digit), we have another 8 options. For the last digit (the ones digit), we again have 8 options.Thus, the 4- digit number can be selected in 7 x 8 x 8 x 8 ways.

I also agree with Brent: since our answer choices have all different units digits, we simply need to calculate the units digit of the product above.

Since 7 x 8 has a units digit of 6, 8 x 8 has a units digit of 4, and 6 x 4 has a units digit of 4, the answer must be 3584.

Answer: B

**Scott Woodbury-Stewart**

Founder and CEO

scott@targettestprep.com

See why Target Test Prep is rated 5 out of 5 stars on BEAT the GMAT. Read our reviews