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An office comprised of eight employees is planning to have a foosball game. A matchup consists of four

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An office comprised of eight employees is planning to have a foosball game. A matchup consists of four

by BTGModeratorVI » Sun Mar 15, 2020 12:44 pm

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An office comprised of eight employees is planning to have a foosball game. A matchup consists of four players, split into pairs. If any employee can be paired up with any other employee, then how many unique matchups result?

(A) 70
(B) 210
(C) 280
(D) 336
(E) 420

Answer: B
Source: Magoosh
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Re: An office comprised of eight employees is planning to have a foosball game. A matchup consists of four

by Jay@ManhattanReview » Sun Mar 15, 2020 9:47 pm
BTGModeratorVI wrote: ↑
Sun Mar 15, 2020 12:44 pm
 An office comprised of eight employees is planning to have a foosball game. A matchup consists of four players, split into pairs. If any employee can be paired up with any other employee, then how many unique matchups result?

(A) 70
(B) 210
(C) 280
(D) 336
(E) 420

Answer: B
Source: Magoosh
Since there's no restriction on who can be part of the matchup, let's select one employee out of 8. Thus, there are 7 employees left for the 2nd player out of 4 players; similarly, there are 6 employees left for the 3rd player out of 4 players; and finally, there are 5 employees left for the 4th player out of 4 players.

Thus, # of unique matchups possible = 7*6*5 = 210.

The correct answer: B

Hope this helps!

-Jay
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Re: An office comprised of eight employees is planning to have a foosball game. A matchup consists of four

by Brent@GMATPrepNow » Tue Mar 17, 2020 6:29 am
BTGModeratorVI wrote: ↑
Sun Mar 15, 2020 12:44 pm
 An office comprised of eight employees is planning to have a foosball game. A matchup consists of four players, split into pairs. If any employee can be paired up with any other employee, then how many unique matchups result?

(A) 70
(B) 210
(C) 280
(D) 336
(E) 420

Answer: B
Source: Magoosh
Take the task of creating a matchup and break it into stages.

Stage 1: Select 4 employees
Since the order in which we select the employees does not matter, we can use combinations.
We can select 4 employees from 8 employees in 8C5 ways (70 ways)
So, we can complete stage 1 in 70 ways

Stage 2: Divide the 4 selected employees into 2 teams
Let's say the 4 selected employees are A, B, C, D
A nice way to determine the number of ways to divide the 4 employees into 2 teams is to find a partner for one person.
For example, let's find a partner for employee A.
NOTE: once we choose a partner for employee A then, by default, the remaining two two employees will be paired together.
In how many ways can we select a partner for employee A? Well, A can be paired with B, C or D
So, we can complete stage 2 in 3 ways

ASIDE: The 3 pairings are:
AB vs CD
AC vs BD
AD vs BC

By the Fundamental Counting Principle (FCP), we can complete the 2 stages (and thus create a matchup) in (70)(3) ways (= 210 ways)

Answer: B

Note: the FCP can be used to solve the MAJORITY of counting questions on the GMAT. For more information about the FCP, watch this free video: https://www.gmatprepnow.com/module/gmat- ... /video/775

You can also watch a demonstration of the FCP in action: https://www.gmatprepnow.com/module/gmat ... /video/776

Then you can try solving the following questions:

EASY
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- https://www.beatthegmat.com/simple-one-t270061.html


MEDIUM
- https://www.beatthegmat.com/combinatoric ... 73194.html
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- https://www.beatthegmat.com/combinatoric ... 67079.html


DIFFICULT
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- https://www.beatthegmat.com/combinations-t123249.html


Cheers,
Brent
Brent Hanneson - Creator of GMATPrepNow.com
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Re: An office comprised of eight employees is planning to have a foosball game. A matchup consists of four

by Scott@TargetTestPrep » Tue Mar 17, 2020 9:15 am
BTGModeratorVI wrote: ↑
Sun Mar 15, 2020 12:44 pm
 An office comprised of eight employees is planning to have a foosball game. A matchup consists of four players, split into pairs. If any employee can be paired up with any other employee, then how many unique matchups result?

(A) 70
(B) 210
(C) 280
(D) 336
(E) 420

Answer: B
Source: Magoosh
First, we select the four players. The number of ways to choose 4 people from 8 is 8C4 = (8 x 7 x 6 x 5)/(4 x 3 x 2) = 2 x 7 x 5 = 70.

Next, we split the four selected players into pairs to form the matchups. Let’s call the individuals A, B, C, and D. There are 3 matchups for these four individuals:

AB vs. CD, AC vs. BD, and AD vs. BC

Since there are 70 ways to select 4 people and each selection has 3 ways of creating matchups, there are a total of 70 x 3 = 210 matchups.

Answer: B

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