Here's how I approached it...we need to select 3 different consonants and 2 different vowels.
Since there are 21 consonants in the alphabet, there are 21 ways to select the first of three consonants. The next consonant must be different, so there are now 20 ways to select the 2nd consonant. The third consonant must be different from the first two selections, so there are 19 ways to select the third consonant.
Therefore, there are 21*20*19 (or P(21,3)) ways of selecting the three consonants.
Since there are 5 vowels in the alphabet, there are 5 ways to select the first of two vowels to be used. The second vowel must be different from the first vowel, so there are 4 ways to select the second vowel.
Therefore, there are 5*4 (or P(5,2)) ways of selecting the two vowels.
Therefore, there are P(21,3) * P(5,2) ways of selecting the 5 letters to be used for our words.
If the question asked only to calculate the number of ways that 3 different consonants and 2 different vowels can be selected from the alphabet, then we'd be done. However, the question asks how many words can be formed, and there are 5! ways to arrange the letters once they are selected.
Then again, maybe I'm just reading the question wrong.
I'm really old, but I'll never be too old to become more educated.