In how many ways can a person post 5 letters in 4 letter boxes ?
(A) 120
(B) 600
(C) 2400
(D) 4^5
(E) 5^5
OA: D
(A) 120
(B) 600
(C) 2400
(D) 4^5
(E) 5^5
OA: D
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Take the task of distributing the 5 letters and break it into stages.RBBmba@2014 wrote:In how many ways can a person post 5 letters in 4 letter boxes ?
(A) 120
(B) 600
(C) 2400
(D) 4^5
(E) 5^5
OA: D
Your solution assumes that each letter box must one letter.madhusudhan237 wrote:HI Brent
In your post, you have considered like: for each letter to get posted, there are 4 letter boxes available.
But, why not in such a way that - I have 4 letter boxes available & 5 letters to post?
In that case,
---------- ---------- ----------- -----------
Letter box-1 Letter box-2 Letter box-3 Letter box-4
So, to post 5 letters
Case1: Letter box-1 has 5 ways (all 5 letters available)
Case2: Letter box-2 has 4 ways (since, only 4 letters are available, one already posted in letter box-1)
Similarly,
Case3, Case4 will have 3, 2 ways
Total (by FCP rule) = 5 x 4 x 3 x 2 = 120 ways
I know, I am wrong! But, I am trying to get into the grove of right thinking
Thanks for your clarification!
Madhu
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