BTGmoderatorDC wrote:Of the 12 temporary employees in a certain company, 4 will be hired as permanent employees. If 5 of the 12 temporary employees are women, how many of the possible groups of 4 temporary employees consist of 3 women and 1 man?
A. 22
B. 35
C. 56
D. 70
E. 105
OA D
Source: Official Guide
We are asked to find the number of ways of choosing 3 women from a group of 5 women and 1 man from a group of 7 men.
Let's first find the number of ways to choose 3 women from 5. Since the order of how the 3 women are chosen doesn't matter, we use combinations:
5C3 = 5!/(3! x 2!) = (5 x 4 x 3)/3! = 60/6 = 10
Similarly, the number of ways to choose 1 man from a group of 7 men is:
7C1 = 7!/(1! x 6!) = 7
Finally, the number of ways to choose 3 women from 5 women and 1 man from 7 men is:
5C3 x 7C1 = 10 x 7 = 70
Answer: D
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