Looking at 2:

y = 0, this means x^2 = 1, wihch means x could be +1 or -1

Now, if x = +1, x + y = 1, whereas if x = -1, x + y = -1

So, statement 2 raises ambiguity, hence not sufficient

kmittal82 wrote:Looking at 2:

y = 0, this means x^2 = 1, wihch means x could be +1 or -1

Now, if x = +1, x + y = 1, whereas if x = -1, x + y = -1

So, statement 2 raises ambiguity, hence not sufficient

Thanks !
I have one more question.
On GMAT, can the square root of 4 be both +2 and -2
I remember there is some rule related to square roots.
But I am not able to recall it.I think I need to take a break :roll:

prachich1987 wrote:

kmittal82 wrote:Looking at 2:

y = 0, this means x^2 = 1, wihch means x could be +1 or -1

Now, if x = +1, x + y = 1, whereas if x = -1, x + y = -1

So, statement 2 raises ambiguity, hence not sufficient

Thanks !
I have one more question.
On GMAT, can the square root of 4 be both +2 and -2
I remember there is some related to it square roots.
But I am not able to recall it.I think I need to take a break :roll:

I would go as far as saying you can bet on the fact GMAT will exploit the fact that sqrt(4) can be +2 or - 2
Speaking of breaks, now is a good time for me to do some work... the kinds I get paid to do

prachich1987 wrote:

kmittal82 wrote:Looking at 2:

y = 0, this means x^2 = 1, wihch means x could be +1 or -1

Now, if x = +1, x + y = 1, whereas if x = -1, x + y = -1

So, statement 2 raises ambiguity, hence not sufficient

Thanks !
I have one more question.
On GMAT, can the square root of 4 be both +2 and -2
I remember there is some related to it square roots.
But I am not able to recall it.I think I need to take a break :roll:

According to the official guide page 114, the sqrt of 4 (or any number) is only the positive root: √4=2, not ±2.

However, x^2=1 is not the same thing: it is a quadratic equation with x, which can have more than one solution - both x=1 and x=-1 will satisfy the equation x^2=1, and so x could equal either of these solutions.

Draw the distinction between roots of numbers (only the positive root) and roots of variables (in which case you need to look at all possible solutions that satisfy the equation).

Thanks Geva!!!