Seamus has 3 times as many marbles as Ronit, and Taj has 7 times as many marbles as Ronit. If Seamus has $s$ marbles,

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Gmat_mission: Legendary Member; Posts: 1622; Joined: Thu Mar 01, 2018 7:22 amFollowed by: 2 members

by Gmat_mission » Sun May 31, 2020 12:58 pm

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Seamus has 3 times as many marbles as Ronit, and Taj has 7 times as many marbles as Ronit. If Seamus has $s$ marbles, then, in terms of $s,$ how many marbles do Seamus, Ronit, and Taj have together?

(A) $\dfrac{3s}7$
(B) $\dfrac{7s}3$
(C) $\dfrac{11s}3$
(D) $7s$
(E) $11s$

[spoiler]OA=C[/spoiler]

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Source: Beat The GMAT — Problem Solving | Sun May 31, 2020 12:58 pm

JamesHammel: Junior | Next Rank: 30 Posts; Posts: 10; Joined: Sun May 31, 2020 4:19 pm

Re: Seamus has 3 times as many marbles as Ronit, and Taj has 7 times as many marbles as Ronit. If Seamus has $s$ marbl

by JamesHammel » Sun May 31, 2020 5:35 pm

First we can determine the amount in the amount Ronit (R) has :
S = 3R
Taj (T) = 7 R
S + T + R = 3R + 7R +R = 11R

Thus, 11R = 11 * S/3 (C)

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Re: Seamus has 3 times as many marbles as Ronit, and Taj has 7 times as many marbles as Ronit. If Seamus has $s$ marbl

by Scott@TargetTestPrep » Wed Mar 31, 2021 8:41 am

Gmat_mission wrote: ↑
Sun May 31, 2020 12:58 pm
Seamus has 3 times as many marbles as Ronit, and Taj has 7 times as many marbles as Ronit. If Seamus has $s$ marbles, then, in terms of $s,$ how many marbles do Seamus, Ronit, and Taj have together?

(A) $\dfrac{3s}7$
(B) $\dfrac{7s}3$
(C) $\dfrac{11s}3$
(D) $7s$
(E) $11s$

[spoiler]OA=C[/spoiler]

Solution:

Since Seamus has s marbles and he has 3 times as many marbles as Ronit, Ronit has s/3 marbles. Since Tai has 7 times as many marbles as Ronit, Tai has 7s/3 marbles. Thus, the 3 individuals together have a total of s + s/3 + 7s/3 = 3s/3 + s/3 + 7s/3 = 11s/3 marbles.

Answer: C

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