Seamus has 3 times as many marbles as Ronit, and Taj has 7 times as many marbles as Ronit. If Seamus has \(s\) marbles,

[Gmat_mission]

Seamus has 3 times as many marbles as Ronit, and Taj has 7 times as many marbles as Ronit. If Seamus has \(s\) marbles, then, in terms of \(s,\) how many marbles do Seamus, Ronit, and Taj have together?

(A) \(\dfrac{3s}7\)
(B) \(\dfrac{7s}3\)
(C) \(\dfrac{11s}3\)
(D) \(7s\)
(E) \(11s\)

[spoiler]OA=C[/spoiler]

Source: Manhattan GMAT

[JamesHammel]

First we can determine the amount in the amount Ronit (R) has :
S = 3R
Taj (T) = 7 R
S + T + R = 3R + 7R +R = 11R

Thus, 11R = 11 * S/3 (C)

[Scott@TargetTestPrep]

Seamus has 3 times as many marbles as Ronit, and Taj has 7 times as many marbles as Ronit. If Seamus has \(s\) marbles, then, in terms of \(s,\) how many marbles do Seamus, Ronit, and Taj have together?

(A) \(\dfrac{3s}7\)
(B) \(\dfrac{7s}3\)
(C) \(\dfrac{11s}3\)
(D) \(7s\)
(E) \(11s\)

[spoiler]OA=C[/spoiler]

Solution:

Since Seamus has s marbles and he has 3 times as many marbles as Ronit, Ronit has s/3 marbles. Since Tai has 7 times as many marbles as Ronit, Tai has 7s/3 marbles. Thus, the 3 individuals together have a total of s + s/3 + 7s/3 = 3s/3 + s/3 + 7s/3 = 11s/3 marbles.

Answer: C