Live GMAT classes with Target Test Prep start Nov 21 and Nov 22. First class free.

See classes
Target Test Prep · GMAT

Choose how you want to prepare

Learn live with an expert or move at your own pace. Every option includes the complete TTP study system.

Newsweek Readers’ Choice Awards 2026 winner: Target Test Prep, #1 Test Prep

Target Test Prep was voted #1 Best Test Prep in the 2026 Newsweek Readers’ Choice™ Awards.

★★★★★5.0563 reviews
GMATLiveTeachStarts Nov 22
Josh Braslow, Target Test Prep GMAT expert
LIVE ONLINE CLASSES

Get Ready for GMAT Test Day Faster with Live Online Classes

with Josh Braslow, 20+ years in test prep

Nov 22 · Josh Braslow
Sun · 9:30 AM to 12:30 PM ET
Included
40 hours of live online classes + 6 months of TTP OnDemand
  • Attend the first class for free
  • Every class is recorded, so you never fall behind
View classes & enroll
Limited seats availableTarget Test Prep
EALiveTeachOnDemandStart anytime
EXECUTIVE ASSESSMENT

Target Test Prep EA OnDemand

Self-paced EA prep. Study on your schedule.

EXECUTIVE ASSESSMENT

with

165+ EA score guarantee
$05-day trial no automatic billing
Schedule
Included
40 hours of live online classes plus six months of access to the complete TTP EA OnDemand course.
  • 165+ EA Score Guarantee
  • 4,100+ Quant, Verbal, and Integrated Reasoning practice questions
  • 400+ hours of in-depth video lessons
  • 3,000+ step-by-step video solutions
View EA class & enroll Start free 5-day trial
Limited cohort · enrollment openTrial includes full course accessTarget Test Prep
GMATOnDemandStart anytime
SELF-PACED MASTERCLASS

Target Test Prep GMAT OnDemand

Complete access from day one. Study on your schedule.

715+ score guarantee
$0to start then $127/mo
  • Personalized study plan and analytics
  • Thousands of lessons and practice questions

Remainders -GMAT PREP

Expert replies
by Stockmoose16 » Wed Nov 12, 2008 7:46 pm
This GMAT prep question has been dealt with a couple times on this board, but I haven't seen anyone post a definitive OA.

Seven different numbers are selected from the integers 1 to 100, and each number is divided by 7. What is the sum of the remainders?

(1) The range of the seven remainders is 6.
(2) The seven numbers selected are consecutive integers.


I think the answer is D, but many seem to think it's B

For (1)
1,2,3,4,5,6,7

have remainders of:

1,2,3,4,5,6,0

That's a range of 6 and the sum of the remainders equals 21

just to double check:

12,13,14,15,16,17,18

have remainders of:

5, 6, 0, 1, 2, 3, 4 = 21

STMNT #1 is sufficient

Stmnt #2

2,3,4,5,6,7,8

have remainders of:

2+3+4+5+6+0+1 = 21 (same as consecutive set tested for stmt #1.

So I get D. Why are people getting B?
Join the discussion
Source: — Data Sufficiency |

by cramya » Wed Nov 12, 2008 7:50 pm
Hi StockMoose,
Refer to https://www.beatthegmat.com/logitech-ds4-t22370.html

Let me know if u still have questions.

Regards,
Cramya
Join the discussion

by Stockmoose16 » Wed Nov 12, 2008 8:00 pm
Cramya,

I believe both of your responses in that thread are incorrect. Your last post says:


I picked the wrong example. Your are right about 7 different numbers but still its B) and not D)

Lets say the numbers are

1 2 3 4 7 6 11

1 2 3 4 7 6 13

Range of the reminders is 6 in both sets but the sum different


The range of the remainders of the first set of numbers above is not 6, it's only 5. Here's why:

The remainder of 1 is 1. The remainder of 2 is 2. The remainder of 3 is 3. The remainder of 4 is 4. The remainder of 5 is 5. The remainder of 6 is 6. The remainder of 7 is 0. The remainder of 11 is 4.

So, the range in that set is from 1-6 ... which is only 5. So your explanation is incorrect.

EDITED: Nevermind, you are correct, the range is 6. Thanks.
Join the discussion

by cramya » Wed Nov 12, 2008 8:05 pm
StockMoose,
Are we cool now? :-)

Good luck for your exam thats coming up!

Regards,
Cramya
Join the discussion

by stop@800 » Thu Nov 13, 2008 10:02 am
A
range of remainder is 6

remainders can be
0 1 2 3 4 5 6
or
0 6 6 6 6 6 6

so insuff


B
7 consecutive intergers
remainder will always
0 1 2 3 4 5 6
so sum can easily be found

hence answer is B

Let me know if you still have any doubt....
Join the discussion

by 4meonly » Mon Nov 17, 2008 10:04 am
summ of 7 conseq integers will be
7x+21
this will be divisible by 7 with R=0 cause 7x and 21 are divisible by 7
Join the discussion