jackcrystal wrote:B ? Yeap, B as in BANANA

Is it really B as in Banana; wow all this time I was thinking its B as in Boy. Thanks Logitech ; You are something!!!

What's the source of this question? I feel the question itself is sufficient unless I am missing something. If I pick 7 different #s and each is divisible by 7, the sum of remainder is 0? Please correct me if I made a mistake.

EricLien9122 wrote:What's the source of this question? I feel the question itself is sufficient unless I am missing something. If I pick 7 different #s and each is divisible by 7, the sum of remainder is 0? Please correct me if I made a mistake. DIVIDED does not mean "divisible" Oh the question is from GMAC. So we are cool! 8)

What's the source of this question? I feel the question itself is sufficient unless I am missing something. If I pick 7 different #s and each is divisible by 7, the sum of remainder is 0? Please correct me if I made a mistake. Hi Eric, The sum of the reminders will be 0 only if u pick all the 7 numbers divisible by 7. In stmt I) we cannot do this since the range will be more than 6. Stmt I is INSUFF Eg: Lets say we pick numbers where the reminders are 1 2 3 4 5 7 7. The range is still 6 but the sum is 29 1 2 3 4 5 6 7 - The range is 6 but the sum is 28 Stmt II SUFF for 7 consecutive intgers the sum of the remainders will always be the same(21) B)

ya, I think I need a new pair of glasses, I read "divisible" instead divide. Story of my life~ Thanks for correcting me btw.

The question said Seven DIFFERENT numbers are selected. Doesn't that mean that the same number can not be repeated twice ? All numbers will be distinct and their range will be 6. These two conditions give 7 consecutive integers in (A) as does (B). I think answer should be (D).

I picked the wrong example. Your are right about 7 different numbers but still its B) and not D) Lets say the numbers are 1 2 3 4 7 6 11 1 2 3 4 7 6 13 Range of the reminders is 6 in both sets but the sum different Hope this helps!

Hi Cramya Sorry I am confused by your last post. 1 2 3 4 7 6 11 1 2 3 4 7 6 13 Are they the remainders? The range will not be 6... also do you have any logic as to picking numbers, why skip 5... thanks!