Rectangle ABCD

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GmatKiss: Legendary Member; Posts: 2789; Joined: Tue Jul 26, 2011 12:19 amFollowed by: 43 members; Location: Chennai, India; Thanked: 206 times; GMAT Score:640

by GmatKiss » Sat Oct 22, 2011 7:42 am

In Rectangle ABCD (BC > AB), E is the point of intersection of diagonals. If (Angle) ABD is twice than (Angle) EAD, what is the value of (Angle) CED?

A. 30 degrees
B. 45 degrees
C. 60 degrees
D. 90 degrees
E. 120 degrees

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Source: Beat The GMAT — Problem Solving | Sat Oct 22, 2011 7:42 am

neelgandham: Community Manager; Posts: 1060; Joined: Fri May 13, 2011 6:46 amFollowed by: 52 members; Location: Utrecht, The Netherlands; Thanked: 318 times

by neelgandham » Sat Oct 22, 2011 8:26 am

Angle AEB = CED = x (Vertical opposite angles are equal)

Interior angle between two sides of a rectangle = 90 = 2p+p => p = 30

Sum of angles in a triangle AEB = 180 = 2p + 2p + x => 180 = 120 + x => x = 60 Option C

Anil Gandham
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