Live GMAT classes with Target Test Prep start Nov 21 and Nov 22. First class free.

See classes
Target Test Prep · GMAT

Choose how you want to prepare

Learn live with an expert or move at your own pace. Every option includes the complete TTP study system.

Newsweek Readers’ Choice Awards 2026 winner: Target Test Prep, #1 Test Prep

Target Test Prep was voted #1 Best Test Prep in the 2026 Newsweek Readers’ Choice™ Awards.

★★★★★5.0563 reviews
GMATLiveTeachStarts Nov 22
Josh Braslow, Target Test Prep GMAT expert
LIVE ONLINE CLASSES

Get Ready for GMAT Test Day Faster with Live Online Classes

with Josh Braslow, 20+ years in test prep

Nov 22 · Josh Braslow
Sun · 9:30 AM to 12:30 PM ET
Included
40 hours of live online classes + 6 months of TTP OnDemand
  • Attend the first class for free
  • Every class is recorded, so you never fall behind
View classes & enroll
Limited seats availableTarget Test Prep
EALiveTeachOnDemandStart anytime
EXECUTIVE ASSESSMENT

Target Test Prep EA OnDemand

Self-paced EA prep. Study on your schedule.

EXECUTIVE ASSESSMENT

with

165+ EA score guarantee
$05-day trial no automatic billing
Schedule
Included
40 hours of live online classes plus six months of access to the complete TTP EA OnDemand course.
  • 165+ EA Score Guarantee
  • 4,100+ Quant, Verbal, and Integrated Reasoning practice questions
  • 400+ hours of in-depth video lessons
  • 3,000+ step-by-step video solutions
View EA class & enroll Start free 5-day trial
Limited cohort · enrollment openTrial includes full course accessTarget Test Prep
GMATOnDemandStart anytime
SELF-PACED MASTERCLASS

Target Test Prep GMAT OnDemand

Complete access from day one. Study on your schedule.

715+ score guarantee
$0to start then $127/mo
  • Personalized study plan and analytics
  • Thousands of lessons and practice questions
Start free 5-day trial
Read 563 reviewsTarget Test Prep

problem solving Q

Expert replies
Post new topic Post Reply
Subscribe topic
Previous Topic Next Topic
Junior | Next Rank: 30 Posts
Posts: 15
Joined: Mon Aug 01, 2011 6:15 am
Location: vijayawada
Thanked: 1 times
by siddhartha123 » Mon Dec 12, 2011 1:57 am
Dear all,

I was struck up with the following q's can any one
Help me out

1) A and b ran a race of 48o .In the first heat,A gives
B a head start of 48 m and beat him by 1/10 th of a
Minute.In the second heat , A gives B a head start of
144 m and is beaten by 1/30 of a minute. What is
B's speed in m/s

A)12 B)14 C)16 D)18 E)20

Ans:a
[spoiler]

2) $252 is divided among a,b,c so that for every $2 that A
Receieved ,B receives $5 and for every $3 that B recieves ,c
Receives $ 7.find the share of A?

A)15 B)20 C)17 d)27 e)23

Ans: D[/spoiler]
M.siddhartha
Top
Join the discussion
Source: — Problem Solving |
User avatar
Community Manager
Posts: 1060
Joined: Fri May 13, 2011 6:46 amFollowed by: 52 members
Location: Utrecht, The Netherlands
Thanked: 318 times

by neelgandham » Mon Dec 12, 2011 9:35 am
Question 1

Total distance = 480 metres
Let Sa, Sb be the speeds of A and B respectively.

First heat
Time taken by A to complete the race = 480/Sa
Time taken by B to complete the race = (480-48)/Sb
A wins the race by 6 secs, Implies
((480-48)/Sb) - (480/Sa) = 6
48*((9/Sb)-(10/Sa)) = 6 - (equation 1)

Second heat
Time taken by A to complete the race = 480/Sa
Time taken by B to complete the race = (480-144)/Sb
A wins the race by 2 secs, Implies
((480/Sa)-(480-144)/Sb) = 2
48*((10/Sa)-(7/Sb)) = 2 - (equation 2)

Add equation 1 and 2
Sb = 12m/sec
Option A
Anil Gandham
Welcome to BEATtheGMAT | Photography | Getting Started | BTG Community rules | MBA Watch
Check out GMAT Prep Now’s online course at https://www.gmatprepnow.com/
Top
Join the discussion
User avatar
Community Manager
Posts: 1060
Joined: Fri May 13, 2011 6:46 amFollowed by: 52 members
Location: Utrecht, The Netherlands
Thanked: 318 times

by neelgandham » Mon Dec 12, 2011 9:42 am
Question 2

$252 is divided among a,b,c so that for every $2 that A
Receieved ,B receives $5 and for every $3 that B recieves ,c
Receives $ 7.find the share of A?

A)15 B)20 C)17 d)27 e)23

Ratio of the amount A received to the amount B received = 2:5 = 6:15
Ratio of the amount B received to the amount C received = 3:7 = 15:35

Total parts = 6+15+35 = 56
56 parts make 252 (total amount)
6 parts make ?

? = 252*6/56 = 27

Option D

Moving it to the appropriate forum!
Last edited by neelgandham on Mon Dec 12, 2011 3:28 pm, edited 1 time in total.
Anil Gandham
Welcome to BEATtheGMAT | Photography | Getting Started | BTG Community rules | MBA Watch
Check out GMAT Prep Now’s online course at https://www.gmatprepnow.com/
Top
Join the discussion
User avatar
GMAT Instructor
Posts: 15539
Joined: Tue May 25, 2010 12:04 pmFollowed by: 1906 members
Location: New York, NY
Thanked: 13060 times
GMAT Score:790

by GMATGuruNY » Mon Dec 12, 2011 11:55 am
I posted a solution here:

https://www.beatthegmat.com/difficult-ma ... -t429.html
Private tutor exclusively for the GMAT and GRE, with over 20 years of experience.
Followed here and elsewhere by over 1900 test-takers.
I have worked with students based in the US, Australia, Taiwan, China, Tajikistan, Kuwait, Saudi Arabia -- a long list of countries.
My students have been admitted to HBS, CBS, Tuck, Yale, Stern, Fuqua -- a long list of top programs.

As a tutor, I don't simply teach you how I would approach problems.
I unlock the best way for YOU to solve problems.

For more information, please email me (Mitch Hunt) at [email protected].
Student Review #1
Student Review #2
Student Review #3
Top
Join the discussion
Newbie | Next Rank: 10 Posts
Posts: 3
Joined: Mon Dec 05, 2011 11:11 am

by cpschott » Mon Dec 12, 2011 3:22 pm
ratio for second problem

should say 3:7
not
Ratio of the amount B received to the amount C received = 5:7 = 15:35


5:7 not= 15:35
answer is correct since this is just a typo i think
Top
Join the discussion
User avatar
Community Manager
Posts: 1060
Joined: Fri May 13, 2011 6:46 amFollowed by: 52 members
Location: Utrecht, The Netherlands
Thanked: 318 times

by neelgandham » Mon Dec 12, 2011 3:29 pm
Thanks for correcting! Yes, it is a typo
Anil Gandham
Welcome to BEATtheGMAT | Photography | Getting Started | BTG Community rules | MBA Watch
Check out GMAT Prep Now’s online course at https://www.gmatprepnow.com/
Top
Join the discussion
Newbie | Next Rank: 10 Posts
Posts: 4
Joined: Wed Oct 26, 2011 8:56 pm

by [email protected] » Tue Dec 13, 2011 10:04 pm
Question 1

Total distance = 480 metres
Let Sa, Sb be the speeds of A and B respectively.

First heat
Time taken by A to complete the race = 480/Sa
Time taken by B to complete the race = (480-48)/Sb
A wins the race by 6 secs, Implies
((480-48)/Sb) - (480/Sa) = 6
48*((9/Sb)-(10/Sa)) = 6 - (equation 1)

Second heat
Time taken by A to complete the race = 480/Sa
Time taken by B to complete the race = (480-144)/Sb
A wins the race by 2 secs, Implies
((480/Sa)-(480-144)/Sb) = 2
48*((10/Sa)-(7/Sb)) = 2 - (equation 2)

Add equation 1 and 2
Sb = 12m/sec
Option A

Can you show me how did you add the two equations to obtain 12m/s? Thank you!
Top
Join the discussion
User avatar
Community Manager
Posts: 1060
Joined: Fri May 13, 2011 6:46 amFollowed by: 52 members
Location: Utrecht, The Netherlands
Thanked: 318 times

by neelgandham » Wed Dec 14, 2011 1:43 am
Total distance = 480 metres
Let Sa, Sb be the speeds of A and B respectively.

First heat
Time taken by A to complete the race = 480/Sa
Time taken by B to complete the race = (480-48)/Sb
A wins the race by 6 secs, Implies
((480-48)/Sb) - (480/Sa) = 6
48*((9/Sb)-(10/Sa)) = 6 - (equation 1)

Second heat
Time taken by A to complete the race = 480/Sa
Time taken by B to complete the race = (480-144)/Sb
A wins the race by 2 secs, Implies
((480/Sa)-(480-144)/Sb) = 2
48*((10/Sa)-(7/Sb)) = 2 - (equation 2)

Add equation 1 and 2
Sb = 12m/sec
Option A
Can you show me how did you add the two equations to obtain 12m/s? Thank you!
Sure I will.
Equation 1 : 48*((9/Sb)-(10/Sa)) = 6
Equation 2 : 48*((10/Sa)-(7/Sb)) = 2
Let (10/Sa) = A
then
Equation 1 : 48*((9/Sb)-A) = 6
Equation 2 : 48*(A-(7/Sb)) = 2
Implies
Equation 1 : (48*(9/Sb))-48*A) = 6
Equation 2 : 48*A-(48*(7/Sb)) = 2
Add the equations
48*(9/Sb)-48*A + 48*A-48*(7/Sb) = 6+2
48*(9/Sb)-48*(7/Sb)=8
48*((9/Sb)-(7/Sb))=8
((9/Sb)-(7/Sb)) = 8/48
(9-7)/Sb = 1/6
2/Sb = 1/6
Sb = 6*2
Sb = 12m/sec

Let me know if you still find it difficult!
Anil Gandham
Welcome to BEATtheGMAT | Photography | Getting Started | BTG Community rules | MBA Watch
Check out GMAT Prep Now’s online course at https://www.gmatprepnow.com/
Top
Join the discussion
Junior | Next Rank: 30 Posts
Posts: 15
Joined: Mon Aug 01, 2011 6:15 am
Location: vijayawada
Thanked: 1 times

by siddhartha123 » Thu Dec 15, 2011 9:21 am
neelgandham wrote:Question 1

Total distance = 480 metres
Let Sa, Sb be the speeds of A and B respectively.

First heat
Time taken by A to complete the race = 480/Sa
Time taken by B to complete the race = (480-48)/Sb
A wins the race by 6 secs, Implies
((480-48)/Sb) - (480/Sa) = 6
48*((9/Sb)-(10/Sa)) = 6 - (equation 1)

Second heat
Time taken by A to complete the race = 480/Sa
Time taken by B to complete the race = (480-144)/Sb
A wins the race by 2 secs, Implies
((480/Sa)-(480-144)/Sb) = 2
48*((10/Sa)-(7/Sb)) = 2 - (equation 2)

Add equation 1 and 2
Sb = 12m/



Thanks neel ;
M.siddhartha
Top
Join the discussion
Junior | Next Rank: 30 Posts
Posts: 15
Joined: Mon Aug 01, 2011 6:15 am
Location: vijayawada
Thanked: 1 times

by siddhartha123 » Thu Dec 15, 2011 9:23 am
neelgandham wrote:Question 1

Total distance = 480 metres
Let Sa, Sb be the speeds of A and B respectively.

First heat
Time taken by A to complete the race = 480/Sa
Time taken by B to complete the race = (480-48)/Sb
A wins the race by 6 secs, Implies
((480-48)/Sb) - (480/Sa) = 6
48*((9/Sb)-(10/Sa)) = 6 - (equation 1)

Second heat
Time taken by A to complete the race = 480/Sa
Time taken by B to complete the race = (480-144)/Sb
A wins the race by 2 secs, Implies
((480/Sa)-(480-144)/Sb) = 2
48*((10/Sa)-(7/Sb)) = 2 - (equation 2)

Add equation 1 and 2
Sb = 12m/



Thanks neel ;
M.siddhartha
Top
Join the discussion