are you sure something is not missing here in question? this question seems incomplete.

surfing, i happened to find the correct form of question
here is the link:

https://www.manhattangmat.com/forums/mgm ... t5760.html

Let m = 1111, *m* = (3*1)*(5*1)*(7*1)*(11*1)
Let n = 5511, *n* = (3*5)*(5*5)*(7*1)*(11*1) = 25 * (3*1)*(5*1)*(7*1)*(11*1) = 25 * *m*
n - m = 5511 - 1111 = 4400, Hmm. Alright, Let me try with another number

Let m = 1111, *m* = (3*1)*(5*1)*(7*1)*(11*1)
Let n = 1155, *n* = (3*1)*(5*1)*(7*5)*(11*5) = 25 * (3*1)*(5*1)*(7*1)*(11*1) = 25 * *m*
n - m = 1155 - 1111 = 44. Oops

Sanju sirjee, Is the question CORRECT ?, or Am I missing a thing ?

neelgandham wrote:Let m = 1111, *m* = (3*1)*(5*1)*(7*1)*(11*1)
Let n = 5511, *n* = (3*5)*(5*5)*(7*1)*(11*1) = 25 * (3*1)*(5*1)*(7*1)*(11*1) = 25 * *m*
n - m = 5511 - 1111 = 4400, Hmm. Alright, Let me try with another number

Let m = 1111, *m* = (3*1)*(5*1)*(7*1)*(11*1)
Let n = 1155, *n* = (3*1)*(5*1)*(7*5)*(11*5) = 25 * (3*1)*(5*1)*(7*1)*(11*1) = 25 * *m*
n - m = 1155 - 1111 = 44. Oops

Sanju sirjee, Is the question CORRECT ?, or Am I missing a thing ?

Oh yeah! I missed a big thing. Edited

This account is the punishment of posting erroneous matter previously:

What must be taken out of it is that m is a 4-digit number with s in its 100th place, such that

*m* = (3^r) (5^s) (7^t) (11^u) and

*n* = (25) (*m*) = (5^2) (3^r) (5^s) (7^t) (11^u) = (3^r) [5^ (s + 2)] (7^t) (11^u).

Hence n is another 4-digit number whose 100th digit is (s + 2), and the other 3 digits are quite the same as that of m. To get the value of n - m, we can do the subtraction work as under:

n = r (s + 2) t u

m = r s t u

(-)
----------------------
n - m = [spoiler]0200
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Take B[/spoiler]