Jim and Renee will play one game of Rock, Paper, Scissors. In this game, each will select and show a hand sign for one of the three items. Rock beats Scissors, Scissors beat Paper, and Paper beats Rock. Assuming that both Jim and Renee have an equal chance of choosing any one of the hand signs, what is the probability that Jim will win? A) 5/6 B) 2/3 C) 1/2 D) 5/12 E) 1/3 OA : after some time

prachich1987 wrote:Jim and Renee will play one game of Rock, Paper, Scissors. In this game, each will select and show a hand sign for one of the three items. Rock beats Scissors, Scissors beat Paper, and Paper beats Rock. Assuming that both Jim and Renee have an equal chance of choosing any one of the hand signs, what is the probability that Jim will win? A) 5/6 B) 2/3 C) 1/2 D) 5/12 E) 1/3 OA : after some time one expert and myself solved this problem here https://www.beatthegmat.com/probability- ... tml#330450 please check and feed back

Night reader wrote:prachich1987 wrote:Jim and Renee will play one game of Rock, Paper, Scissors. In this game, each will select and show a hand sign for one of the three items. Rock beats Scissors, Scissors beat Paper, and Paper beats Rock. Assuming that both Jim and Renee have an equal chance of choosing any one of the hand signs, what is the probability that Jim will win? A) 5/6 B) 2/3 C) 1/2 D) 5/12 E) 1/3 OA : after some time one expert and myself solved this problem here https://www.beatthegmat.com/probability- ... tml#330450 please check and feed back Thanks Night reader. I though that both of them can't pick the same thing anyways very nice explanation given by you