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John's car dealership contains m cars, 20% of which...

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by swerve » Sun Jan 28, 2018 6:55 am
John's car dealership contains m cars, 20% of which are minivans and 80% are sedans. Kevin's car dealership contains n cars, 40% of which are minivans and 60% are trucks. Larry's car dealership contains p cars, 50% of which are minivans and 50% of which are convertibles. If 25% of the m + n + p cars contained at the three dealerships are minivans, what is m in terms of n and p?

A. n + 3p
B. 3n + 5p
C. 4n + 5p
D. (n + 5p)/2
E. (4n + 5p)/3

The OA is B.

Please, can any expert explain this PS question for me? I can't get the correct answer and I would like to know how to solve it in less than 2 minutes. I need your help. Thanks.
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by DavidG@VeritasPrep » Sun Jan 28, 2018 11:55 am
swerve wrote:John's car dealership contains m cars, 20% of which are minivans and 80% are sedans. Kevin's car dealership contains n cars, 40% of which are minivans and 60% are trucks. Larry's car dealership contains p cars, 50% of which are minivans and 50% of which are convertibles. If 25% of the m + n + p cars contained at the three dealerships are minivans, what is m in terms of n and p?

A. n + 3p
B. 3n + 5p
C. 4n + 5p
D. (n + 5p)/2
E. (4n + 5p)/3

The OA is B.

Please, can any expert explain this PS question for me? I can't get the correct answer and I would like to know how to solve it in less than 2 minutes. I need your help. Thanks.
# of minivans at John's dealership: .20m
# of minivans at Kevin's dealership: .40n
# of minivans at Larry's dealership: ..50p
Total# minivans: .25(m + n + p)

Thus, .20m + .40n + .50p = .25(m + n + p)
20m + 40n + 50p = 25m + 25n + 25p
15n + 25p = 5m
3n + 5p = m

The correct answer is B
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by DavidG@VeritasPrep » Sun Jan 28, 2018 12:02 pm
swerve wrote:John's car dealership contains m cars, 20% of which are minivans and 80% are sedans. Kevin's car dealership contains n cars, 40% of which are minivans and 60% are trucks. Larry's car dealership contains p cars, 50% of which are minivans and 50% of which are convertibles. If 25% of the m + n + p cars contained at the three dealerships are minivans, what is m in terms of n and p?

A. n + 3p
B. 3n + 5p
C. 4n + 5p
D. (n + 5p)/2
E. (4n + 5p)/3

The OA is B.

Please, can any expert explain this PS question for me? I can't get the correct answer and I would like to know how to solve it in less than 2 minutes. I need your help. Thanks.
(Notice, that this question is conceptually nearly identical to this one: https://www.beatthegmat.com/need-help-wi ... tml#780012
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by Scott@TargetTestPrep » Sun Jul 28, 2019 8:35 am
swerve wrote:John's car dealership contains m cars, 20% of which are minivans and 80% are sedans. Kevin's car dealership contains n cars, 40% of which are minivans and 60% are trucks. Larry's car dealership contains p cars, 50% of which are minivans and 50% of which are convertibles. If 25% of the m + n + p cars contained at the three dealerships are minivans, what is m in terms of n and p?

A. n + 3p
B. 3n + 5p
C. 4n + 5p
D. (n + 5p)/2
E. (4n + 5p)/3
We can create the equation:

0.2m + 0.4n + 0.5p = 0.25(m + n + p)

Multiplying the equation by 100, we have:

20m + 40n + 50p = 25m + 25n + 25p

15n + 25p = 5m

3n + 5p = m

Answer: B

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