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Notice that 1.5% is the midpoint between 1% and 2%. So if you had only 1% milk (x) and 2% milk (y), and the combined solution was 1.5% fat, you'd have equal amounts of x and y. If z = 0, we won't have any 3% milk to worry about. Put another way, if z = 0, then x = y. So we can plug in 0 for z in the answer choices, and see what gives us y by itself.Three grades of milk: 1%, 2%, and 3% fat by volume. x gallons of 1%, y gallons of 2%, and z gallons of 3% are mixed to give x + y + z gallons of 1.5%. What is x in terms of y and z?
a) y + 3z
b) (y + z)/4
c) 2y + 3z
d) 3y + z
e) 3y + 4z
Let's start with a "word equation" and slowly turn it into an algebraic expression:Three grades of milk: 1%, 2%, and 3% fat by volume. X gallons of 1%, y gallons of 2%, and z gallons of 3% are mixed to give x + y + z gallons of 1.5%. What is x in terms of y and z?
a. y + 3z
b. (y + z)/4
c. 2y + 3z
d. 3y + z
e. 3y + 4z
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