BREAKING: Target Test Prep releases Brand New 2026 On Demand GMAT prep course

Redeem
TTP OnDemand GMAT Video Course
Featured Course

Target Test Prep GMAT OnDemand

Scott Woodbury-Stewart’s private virtual classroom — 400 hours of master-class video lessons for the GMAT Focus Edition.

  • 715+ score guarantee — highest in the industry (99th percentile)
  • 52 chapters · 1,500+ lessons · 4,000+ practice questions
  • 400 hours of video · 1,500+ instructor-led HD smartboard lessons
  • 300,000+ students accepted to Harvard, Stanford, Wharton, Booth & Sloan & more
  • 24/7 live support + weekly Zoom office hours with GMAT instructors
  • TTP AI Assist — 24/7 AI-powered virtual tutor for instant help
  • 1,200+ flashcards + AI-powered study assistant & daily calendar
  • OnDemand, LiveTeach & GMAT Bootcamp formats available
  • Also: GRE, SAT Math & Executive Assessment courses
  • MBA Admissions Consulting now available
  • 🏆 2025 EdTech Breakthrough Award: Test Prep Solution Provider of the Year
  • 200,000+ students served
  • 5-day free trial — $0 to start, no auto-billing, cancel anytime
★★★★★ 5.0 (559 reviews)
130-pt guarantee
$0 to start then $127/mo
Start Free 5-Day Trial Read 559 Reviews →

doubt here

Expert replies
Post new topic Post Reply
Previous Topic Next Topic
Master | Next Rank: 500 Posts
Posts: 113
Joined: Mon Apr 26, 2010 8:58 amFollowed by: 14 members
Thanked: 2 times
by divya23 » Wed Jun 15, 2011 6:01 am
we have to find the remainder when x is divided by 6.
wen x is divided by 2 remainder is 1 and when x is divided by 3 remainder is 0

here wen we solve this we get the value of x as 3,9,15
now both 9 and 15 when divided by 6 give the remainder as 3 but it is not posible wen x = 3

how is then this stmnt sufficient

please reply
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Source: — Problem Solving |

GMAT/MBA Expert

User avatar
GMAT Instructor
Posts: 3835
Joined: Fri Apr 02, 2010 10:00 pmFollowed by: 523 members
Location: Milpitas, CA
Thanked: 1854 times
GMAT Score:770

by Anurag@Gurome » Wed Jun 15, 2011 6:09 am
divya23 wrote:...now both 9 and 15 when divided by 6 give the remainder as 3 but it is not posible wen x = 3
When 3 is divided by 6, the remainder is 3.
Anurag Mairal, Ph.D., MBA
GMAT Expert, Admissions and Career Guidance
Gurome, Inc.
1-800-566-4043 (USA)

Join Our Facebook Groups
GMAT with Gurome
https://www.facebook.com/groups/272466352793633/
Admissions with Gurome
https://www.facebook.com/groups/461459690536574/
Career Advising with Gurome
https://www.facebook.com/groups/360435787349781/
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
User avatar
GMAT Instructor
Posts: 199
Joined: Tue May 17, 2011 6:06 amFollowed by: 121 members
Location: Cambridge, MA
Thanked: 192 times
GMAT Score:780

by Ashley@VeritasPrep » Wed Jun 15, 2011 11:30 am
Just adding one thing here, something that may be useful in terms of generalizing this concept to other problems. If you are ever told that "when x is divided by 2, the remainder is 1," that's the exact same thing as being told that "x is odd." (And of course, being told that "when x is divided by n, the remainder is 0" is the same as being told that "x is a multiple of n".) So in this particular problem, we are effectively being told that "x is an odd multiple of 3." Multiples of *any* odd number n will flip-flop odd to even to odd to even to odd and so on. The even ones will always be multiples of 2n; the odd ones will always yield a remainder of n when divided by 2n.

For instance, considering the remainders when multiples of 7
7 14 21 28 35 42 49 56 63 70 77 84 ...
are divided by 14, I'll get
7 0 7 0 7 0 7 0 7 0 7 0 ...

Works every time :)
Ashley Newman-Owens
GMAT Instructor
Veritas Prep

Post helpful? Mosey your cursor on over to that Thank button and click, please! I will bake you an imaginary cake.
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Junior | Next Rank: 30 Posts
Posts: 11
Joined: Thu May 19, 2011 10:32 pm

by jkati » Thu Jun 16, 2011 10:04 pm
here we have that x is divisible by 3 and when divided by 2 we will get the remainder 1 so for example choose the numbers for this condition = 3, 9,15,21,27,33,39.....


when we divide these numbers by 6 in every case we will get the remainder as 3.

so the answer should be 3
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Post new topic Post Reply
• Page 1 of 1