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cigar-word problem

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by kishokbabu » Tue Dec 13, 2011 10:26 am
A Cuban cigar would cost 1 dollar less than 1.5 times a French cigar, had the French cigar cost 0.7 dollar less than it does now. An Arabian cigar costs 50 cents more than 1.5 times the Cuban cigar. The three cigars together cost 74.70 dollars. What is the price of the French cigar?

a) $16.70
b) $23
c) $25.50
d) $35
e) $37.40

Pls help to solve this problem
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by rijul007 » Tue Dec 13, 2011 10:42 am
Cuban cigar = $c
French .. = $f
Arabian .. = $a

c+f+a = 74.7

c = 3(f-0.7)/2 - 1
f = 2(c+1)/3 + 0.7
a = 3c/2 + 0.5

c+f+a = 74.7
c+ 2(c+1)/3 +0.7 + 3c/2 +0.5 = 74.7
c = $23

Put this in
c = 3(f-0.7)/2 - 1

f = $16.70

Option A
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by neelgandham » Tue Dec 13, 2011 10:54 am
An Arabian cigar costs 50 cents more than 1.5 times the Cuban cigar. The three cigars together cost 74.70 dollars. What is the price of the French cigar?


Let the cost of a Cuban Cigar be $C and
Let the cost of a French Cigar be $F and
Let the cost of an Arabian Cigar be $A

A Cuban cigar would cost 1 dollar less than 1.5 times a French cigar,had the French cigar cost 0.7 dollar less than it does now. Implies
$C = (1.5*($F-0.7))-1

An Arabian cigar costs 50 cents more than 1.5 times the Cuban cigar. Implies
$A= (1.5*$C) + 0.5

The three cigars together cost 74.70 dollars.Implies
$C+$F+$A=$74.70

((1.5*($F-0.7))-1) + $F + (1.5*((1.5*($F-0.7))-1)) + 0.5 = 74.7
Implies $F = $16.70
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by Mdewan » Tue Dec 13, 2011 10:57 am
Ans: A
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by kishokbabu » Tue Dec 13, 2011 10:58 am
Hi rijul,

How u r getting the second equation
f = 2(c+1)/3 + 0.7

Pls explain hw u arrive the above eqn.

rijul007 wrote:Cuban cigar = $c
French .. = $f
Arabian .. = $a

c+f+a = 74.7

c = 3(f-0.7)/2 - 1
f = 2(c+1)/3 + 0.7
a = 3c/2 + 0.5

c+f+a = 74.7
c+ 2(c+1)/3 +0.7 + 3c/2 +0.5 = 74.7
c = $23

Put this in
c = 3(f-0.7)/2 - 1

f = $16.70

Option A
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by rijul007 » Tue Dec 13, 2011 11:03 am
kishokbabu wrote:Hi rijul,

How u r getting the second equation
f = 2(c+1)/3 + 0.7

Pls explain hw u arrive the above eqn.

rijul007 wrote:Cuban cigar = $c
French .. = $f
Arabian .. = $a

c+f+a = 74.7

c = 3(f-0.7)/2 - 1
f = 2(c+1)/3 + 0.7
a = 3c/2 + 0.5

c+f+a = 74.7
c+ 2(c+1)/3 +0.7 + 3c/2 +0.5 = 74.7
c = $23

Put this in
c = 3(f-0.7)/2 - 1

f = $16.70

Option A
@kishokbabu
I jst manipulated the expression
c = 3(f-0.7)/2 - 1


c = 3(f-0.7)/2 - 1

3(f-0.7)/2 = c+1
f-0.7 = 2(c+1)/3
f = 2(c+1)/3 + 0.7
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