BREAKING: Target Test Prep releases Brand New 2026 On Demand GMAT prep course

Redeem

Target Test Prep · GMAT

Choose how you want to prepare

Learn live with an expert or move at your own pace. Every option includes the complete TTP study system.

★★★★★5.0559 reviews
GMATLiveTeach Starts Oct 17
Chris Peckover, Target Test Prep GMAT expert
LIVE ONLINE CLASSES

Get Ready for GMAT Test Day Faster with Live Online Classes

with Chris Peckover, 100th-Percentile GMAT Scorer

Oct 17 · Chris Peckover
Sat · 11:00 AM to 2:00 PM ET
Oct 20 · Chris Peckover
Tue, Thu · 8:00 to 10:00 PM ET
Oct 25 · Josh Braslow
Sun · 1:00 to 4:00 PM ET
Included
40 hours of live online classes + 6 months of TTP OnDemand
  • Attend the first class for free
  • Every class is recorded, so you never fall behind
View classes & enroll
Limited seats availableTarget Test Prep
EALiveTeachOnDemand 5 seats left Start anytime
EXECUTIVE ASSESSMENT

Target Test Prep EA OnDemand

Self-paced EA prep. Study on your schedule.

Logan Thompson
EXECUTIVE ASSESSMENT

Sep 6 to Dec 6, 2026

with Logan Thompson

165+ EA score guarantee
$05-day trial no automatic billing
Schedule
Sun · 9:30 AM to 12:30 PM ET
Included
40 hours of live online classes plus six months of access to the complete TTP EA OnDemand course.
  • 165+ EA Score Guarantee
  • 4,100+ Quant, Verbal, and Integrated Reasoning practice questions
  • 400+ hours of in-depth video lessons
  • 3,000+ step-by-step video solutions
View EA class & enroll Start free 5-day trial
Limited cohort · enrollment openTrial includes full course accessTarget Test Prep
GMATOnDemand Start anytime
SELF-PACED MASTERCLASS

Target Test Prep GMAT OnDemand

Complete access from day one. Study on your schedule.

715+ score guarantee
$0to start then $127/mo
  • Personalized study plan and analytics
  • Thousands of lessons and practice questions

Compare the format, schedule, and included access before enrolling. Prices and seat counts shown reflect the supplied offer details.

Any Idea?

Expert replies
Source: — Problem Solving |

by rijul007 » Tue Nov 01, 2011 10:11 am
hypotenuse = a
each side = a/root(2)

Perimeter of rt isosceles triangle = a + 2a/root(2) = a+a*root(2) = 16+16*root(2)


so hypotenuse = 16
Option B
Join the discussion

by gmatblood » Tue Nov 01, 2011 10:19 am
Is it 8ROOT2 ?
Join the discussion

by saketk » Tue Nov 01, 2011 11:03 am
The easiest way is to plug the answer choices [ remember to start with smart choices ]


2a^2 = b^2 (b is the hypotenuse)

or, a = b/sqrt(2) = b*sqrt(2)/2 -- THIS IS OUR MAIN EXPRESSION.

By smart choices I mean -- look at the perimeter.. It has root2 in it. So start with choices where you don't have ROOT(2) because our expression above has already got one.

Put the choices and see whether the value satisfies this equation .. 2a+b = 16+16*sqrt(2).

this will take 45-60 secs.

hth

IMO [spoiler](16) [/spoiler] the correct answer.
Join the discussion

by LalaB » Wed Nov 02, 2011 1:06 am
2a^2=h^2
a=h/sqroot2

2*h/sqroot2+h=16+16*sqroot2

sqroot2*h+h=16+16*sqroot2
h*(sqroot2+1)=16(sqroot2+1)

h=16
Join the discussion

by vaibhavgupta » Wed Nov 02, 2011 2:22 pm
fbgeoff wrote:Image
IMO D

WHTS the OA?
If OA is A, IMO B
If OA is B, IMO C
If OA is C, IMO D
If OA is D, IMO E
If OA is E, IMO A

FML!! :/
Join the discussion

by neelgandham » Wed Nov 02, 2011 2:39 pm
Let the length of the perpendicular sides be a, Hypotenuse = a*Square root(2) = ?

16 + 16*(Square root(2)) = a+a+(a*Square root(2))

16*(1+(Square root(2)) = a*Square root(2)* (1+(Square root(2))

16 = a*Square root(2) = Hypotenuse !

IMO : B

vaibhavgupta - I reckon you calculated the side, and not the Hypotenuse
Anil Gandham
Welcome to BEATtheGMAT | Photography | Getting Started | BTG Community rules | MBA Watch
Check out GMAT Prep Now's online course at https://www.gmatprepnow.com/
Join the discussion

by fbgeoff » Wed Nov 02, 2011 7:33 pm
Correct answer according to the GMATPrep is B
Join the discussion

by vaibhavgupta » Thu Nov 03, 2011 1:28 am
neelgandham wrote:Let the length of the perpendicular sides be a, Hypotenuse = a*Square root(2) = ?

16 + 16*(Square root(2)) = a+a+(a*Square root(2))

16*(1+(Square root(2)) = a*Square root(2)* (1+(Square root(2))

16 = a*Square root(2) = Hypotenuse !

IMO : B

vaibhavgupta - I reckon you calculated the side, and not the Hypotenuse
:?

Hmm.. will keep this in mind, thanks :)
If OA is A, IMO B
If OA is B, IMO C
If OA is C, IMO D
If OA is D, IMO E
If OA is E, IMO A

FML!! :/
Join the discussion