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A rectangular box

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by GmatKiss » Tue Nov 01, 2011 4:46 am
A rectangular box is 10 inches wide, 10 inches long,
and 5 inches high. What is the greatest possible
(straight-line) distance, in inches, between any two
points on the box?

(A) 15
(B) 20
(C) 25
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by Anurag@Gurome » Tue Nov 01, 2011 4:53 am
GmatKiss wrote:A rectangular box is 10 inches wide, 10 inches long, and 5 inches high. What is the greatest possible (straight-line) distance, in inches, between any two points on the box?
Greatest possible distance between any two points in a rectangular parallelogram is the length of main diagonal.

Length of main diagonal of the box = √(10² + 10² + 5²) = √225 = 15

The correct answer is A.
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by shankar.ashwin » Tue Nov 01, 2011 4:53 am
Longest distance would be the diagonal of the box;
Srrt(100+100+25) = 15
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by sam2304 » Tue Nov 01, 2011 4:54 am
Greatest possible distance = sqrt(10^2 + 10^2 + 5^2) = sqrt(225) = 15

IMO A.
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by neelgandham » Tue Nov 01, 2011 4:56 am
GmatKiss wrote:A rectangular box is 10 inches wide, 10 inches long,
and 5 inches high. What is the greatest possible
(straight-line) distance, in inches, between any two
points on the box?

(A) 15
(B) 20
(C) 25
Option A Attachment is completely out of scale :D
You do not have the required permissions to view the files attached to this post.
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by Brent@GMATPrepNow » Tue Nov 01, 2011 5:49 am
If you'd like to try a related question, with video solution, you can watch video #12 at https://www.gmatprepnow.com/module/gmat-geometry (it's free).

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