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by neelgandham » Thu Oct 27, 2011 2:53 am
lenagmat wrote:Is (x/m)*(m^2+n^2+k^2)=xm+yn+zk ?

1). z/k=x/m
2). x/m=y/n
Option C

Rephrasing the question u get is ((x*n*n)+(x*k*k))/m = y*n+z*k

from 1)
z/k=x/m
((x*n*n)+(x*k*k))/m = zk + ((x*n*n)/m) - Insufficient

from 2
x/m=y/n
((x*n*n)+(x*k*k))/m = yn + ((x*k*k)/m) - Insufficient

Using both
((x*n*n)+(x*k*k))/m = y*n+z*k
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by lenagmat » Thu Oct 27, 2011 4:24 am
A little bit don't understand where xm^2 and xm?
neelgandham wrote:
lenagmat wrote:Is (x/m)*(m^2+n^2+k^2)=xm+yn+zk ?

Rephrasing the question u get is ((x*n*n)+(x*k*k))/m = y*n+z*k
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by neelgandham » Thu Oct 27, 2011 4:39 am
lenagmat wrote:A little bit don't understand where xm^2 and xm?
neelgandham wrote:
lenagmat wrote:Is (x/m)*(m^2+n^2+k^2)=xm+yn+zk ?

Rephrasing the question u get is ((x*n*n)+(x*k*k))/m = y*n+z*k
Here it is...

Is (x/m)*(m^2+n^2+k^2)=xm+yn+zk ?
Is ((x/m)*(m^2))+((x/m)*(n^2))+((x/m)*(k^2)) = xm+yn+zk ?
Is xm + +((x/m)*(n^2))+((x/m)*(k^2)) = xm+yn+zk ?
Subtract xm from both the sides
Is ((x/m)*(n^2))+((x/m)*(k^2)) = yn+zk ?
Is ((x*n*n)+(x*k*k))/m = y*n+z*k ?
Anil Gandham
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by lenagmat » Thu Oct 27, 2011 6:11 am
I am trying but I cannot get why insted of yn and zk we put ((x*n*n)/m) and ((x*k*k)/m).

Sorry may be it is easy but I just cannot get it.
neelgandham wrote:
lenagmat wrote:Is (x/m)*(m^2+n^2+k^2)=xm+yn+zk ?

from 1)
z/k=x/m
((x*n*n)+(x*k*k))/m = zk + ((x*n*n)/m) - Insufficient

from 2
x/m=y/n
((x*n*n)+(x*k*k))/m = yn + ((x*k*k)/m) - Insufficient

Using both
((x*n*n)+(x*k*k))/m = y*n+z*k
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