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Option Clenagmat wrote:Is (x/m)*(m^2+n^2+k^2)=xm+yn+zk ?
1). z/k=x/m
2). x/m=y/n
neelgandham wrote:lenagmat wrote:Is (x/m)*(m^2+n^2+k^2)=xm+yn+zk ?
Rephrasing the question u get is ((x*n*n)+(x*k*k))/m = y*n+z*k
lenagmat wrote:A little bit don't understand where xm^2 and xm?
Here it is...neelgandham wrote:lenagmat wrote:Is (x/m)*(m^2+n^2+k^2)=xm+yn+zk ?
Rephrasing the question u get is ((x*n*n)+(x*k*k))/m = y*n+z*k
Is (x/m)*(m^2+n^2+k^2)=xm+yn+zk ?
Is ((x/m)*(m^2))+((x/m)*(n^2))+((x/m)*(k^2)) = xm+yn+zk ?
Is xm + +((x/m)*(n^2))+((x/m)*(k^2)) = xm+yn+zk ?
Subtract xm from both the sides
Is ((x/m)*(n^2))+((x/m)*(k^2)) = yn+zk ?
Is ((x*n*n)+(x*k*k))/m = y*n+z*k ?
neelgandham wrote:lenagmat wrote:Is (x/m)*(m^2+n^2+k^2)=xm+yn+zk ?
from 1)
z/k=x/m
((x*n*n)+(x*k*k))/m = zk + ((x*n*n)/m) - Insufficient
from 2
x/m=y/n
((x*n*n)+(x*k*k))/m = yn + ((x*k*k)/m) - Insufficient
Using both
((x*n*n)+(x*k*k))/m = y*n+z*k
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