A men's basketball league assigns every player a two-digit number

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A men's basketball league assigns every player a two-digit number for the back of his jersey. If the league uses only the digits 1-5, what is the maximum number of players that can join the league such that no player has a number with a repeated digit (e.g. 22), and no two players have the same number?

A. 20
B. 21
C. 22
D. 24
E. 25

Answer: A
Source: Manhattan prep

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BTGModeratorVI wrote:
Mon Apr 13, 2020 3:39 pm
A men's basketball league assigns every player a two-digit number for the back of his jersey. If the league uses only the digits 1-5, what is the maximum number of players that can join the league such that no player has a number with a repeated digit (e.g. 22), and no two players have the same number?

A. 20
B. 21
C. 22
D. 24
E. 25

Answer: A
Source: Manhattan prep
Take the task of creating different jersey numbers and break it into stages.

Stage 1: Select the first digit
There are 5 digits (1, 2, 3, 4, or 5) to choose from, so we can complete stage 1 in 5 ways

Stage 2: Select the second digit
Repeated digits are NOT ALLOWED.
So, once we select the 1st digit in stage 1, we cannot select it again.
So, there are 4 digits remaining to choose from.
We can complete stage 2 in 4 ways

By the Fundamental Counting Principle (FCP), we can complete the two stages (and thus create the 2-digit jersey numbers) in (5)(4) ways ( = 20 ways)

Answer: A

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BTGModeratorVI wrote:
Mon Apr 13, 2020 3:39 pm
A men's basketball league assigns every player a two-digit number for the back of his jersey. If the league uses only the digits 1-5, what is the maximum number of players that can join the league such that no player has a number with a repeated digit (e.g. 22), and no two players have the same number?

A. 20
B. 21
C. 22
D. 24
E. 25

Answer: A
Source: Manhattan prep
Solution:

We need to determine how many two-digit numbers can be created from 5 digits (1 to 5, inclusive), with no repeated digits. Since order matters, we have a permutation. Thus, the number of ways to create two-digit numbers is 5P2 = 5!/(5 - 2)! = 5 x 4 = 20.

Alternate Solution:

If repeated digits were allowed, there would be 25 possibilities since, for each digit, we would have 5 choices. Among these 25 possibilities, 5 of them are repeated digit numbers (which are 11, 22, 33, 44, and 55). Thus, without the repeated digits, there are 25 - 5 = 20 numbers possible.

Answer: A

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