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by truplayer256 » Mon May 11, 2009 5:34 pm
a+1/(cb+1/c)=16/5
a+c/cb+1=16/5
acb+a+c/cb+1=16/5

acb+a+c=16
cb+1=5
cb=4

5a+c=16
a=3
c=1
b=4

3+1+4=8 B.
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by truplayer256 » Wed May 13, 2009 6:30 am
What's the OA?
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by dtweah » Wed May 13, 2009 6:50 am
truplayer256 wrote:What's the OA?
You nailed the Truplayer but the OA thinks you could have saved some time. It wants you to decompose a fraction instead of composing it.

(b) Since 1/(b + 1/c) < 1 then a = 3 and (b + 1/c) = 5. Since 1/c <= 1 then b = 4 and c = 1.

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So in other words what they are saying
16/5=3 + 1/5= 3 +1/(1+4/1).

We got to be thinking something like this when you are given only one equation with 3 unknowns, just to save time and avoid errors.
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