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y miles and a triangle

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Master | Next Rank: 500 Posts
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by shibal » Fri May 01, 2009 11:03 am
a cornfield is like a right triangle. it has hypotenuse equal to y and height equal to y/2. If y^2=2, what is the area of the field?
Last edited by shibal on Fri May 01, 2009 11:46 am, edited 1 time in total.
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by maihuna » Fri May 01, 2009 11:40 am
this is a wrong question if hyp = underroot 2 and height =2?????
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by shibal » Fri May 01, 2009 11:47 am
i edit the question.... typo... sorry
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by maihuna » Fri May 01, 2009 11:54 am
base^2 = hyp^2 - ht^2
y^2 - y^2/4 = (3/4)y^2
base = (3^1/2/2)y

area = (1/2)*(base*height)
= (1/2)*(y/2)*(3^2/2)*y
= (3^1/2))/8)*y^2
= (3^1/2)/8)*2
= (3^1/2)/4
Last edited by maihuna on Fri May 01, 2009 12:40 pm, edited 1 time in total.
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by shibal » Fri May 01, 2009 12:31 pm
maihuna wrote:base^2 = hyp^2 - ht^2
y^2 - y^2/4 = (3/4)y^2
base = (3/4)y

area = (1/2)*(base*height)
= (1/2)*(y/2)*(3/4)*y
= 3/16*y^2
= (3/16)*2
= 3/8
nope
OA: [spoiler](3^1/2)/4[/spoiler]
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by maihuna » Fri May 01, 2009 12:40 pm
sorry edited my post
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