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XY>1?

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Source: — Data Sufficiency |

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by Rahul@gurome » Wed Nov 24, 2010 4:37 am
mariah wrote:XY>1?
1). X^Y=1
2). Y=-1
Statement 1: X^Y = 1
Implies either (X = 1, Y = Any number) or (X = Any number except zero, Y = 0)
Thus, XY may be < 1 or > 1 or equal to 0.

Not sufficient.

Statement 2: Y = -1
X can be anything.

Not sufficient.

1 & 2 Together: Only possible values of X and Y are X = 1 and Y = -1. Thus XY = -1 < 1

Sufficient.

The correct answer is C.
Last edited by Rahul@gurome on Thu Nov 25, 2010 8:18 am, edited 2 times in total.
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by beat_gmat_09 » Wed Nov 24, 2010 4:56 am
Rahul@gurome wrote: Y = -1
Only possible value of X is 1.
Thus, XY = -1 < 1

Sufficient.
Y = -1, how come value of X is 1. X can be anything, if X = 1 XY< 1, if X = -2 XY>1
Value of X is not given in B.
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by Rahul@gurome » Wed Nov 24, 2010 5:07 am
beat_gmat_09 wrote: Y = -1, how come value of X is 1. X can be anything
Thanks.
I made a terrible mistake!
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by nubu » Wed Nov 24, 2010 7:30 am
X^Y = 1 & Y= -1
=> X^(-1) = 1 <=> 1/(X^1) = 1 <=> X^1 = 1 <=> X = 1

=> XY = -1 < 1

Pick C
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by hitesht » Thu Nov 25, 2010 6:40 am
Hi Rahul, how can the value of X be anything?
considering 1 & 2 together, if X=2 and Y=-1
X^Y = 1/2
So X can be only 1.
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by Rahul@gurome » Thu Nov 25, 2010 8:17 am
hitesht wrote:Hi Rahul, how can the value of X be anything?
considering 1 & 2 together, if X=2 and Y=-1
X^Y = 1/2
So X can be only 1.
That was a typo.
Edited.
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by gdk800 » Thu Nov 25, 2010 10:17 am
I think Rahul's first post says it all. In the first go even i could also come up with X=1 only considering both statements together. Thus OA has to be C with X = 1 and Y = -1.
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