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x(y+z) = 0

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by nervesofsteel » Wed Jul 08, 2009 2:16 pm
If xyz ≠ 0, is x (y + z) = 0?
(1) ¦y + z¦ = ¦y¦ + ¦z¦
(2) ¦x + y¦ =¦x¦ + ¦y¦
A. Statement (1) ALONE is sufficient, but statement (2) alone is not sufficient.
B. Statement (2) ALONE is sufficient, but statement (1) alone is not sufficient.
C. BOTH statements TOGETHER are sufficient, but NEITHER statement ALONE is
sufficient.
D. EACH statement ALONE is sufficient.
E. Statements (1) and (2) TOGETHER are NOT sufficient.

IMO A
but OA C
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Source: — Data Sufficiency |
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by ssmiles08 » Wed Jul 08, 2009 4:59 pm
I agree with you...IMO A.

I don't know how it is C.
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by mehravikas » Wed Jul 08, 2009 5:27 pm
Should be 'A' unless the question is x(y + z) > 0 or x(y + z) < 0
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by shibal » Wed Jul 08, 2009 5:54 pm
why A guys?
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by ssmiles08 » Wed Jul 08, 2009 7:56 pm
shibal wrote:why A guys?
For x*(y + z) = 0

x = 0, or y + z = 0

since x cannot be 0, y must = -z or -y = z

1) tells you that y and z have the same sign.

If y and z have the same sign, then y + z would not equal to 0.

so x*(y + z) = 0 is not possible. SUFF.

2) gives no information about z. Insuff.

(A)
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