is X>Y?
I (x)/(3y) > 1/3
II -x+p < -y+p
I chose D
From I we obtain 3x > 3y
then we divide all by 3 and we get
x > y So it is suff
II -x < - y or x>y
Then again is suff
However the correct answer says that only B is correct and the explanation says that with St 1 X could be either positive or negative and that means it is not sufficient
I don't quite understand the explanation any hint that you provide would be very helpful
I (x)/(3y) > 1/3
II -x+p < -y+p
I chose D
From I we obtain 3x > 3y
then we divide all by 3 and we get
x > y So it is suff
II -x < - y or x>y
Then again is suff
However the correct answer says that only B is correct and the explanation says that with St 1 X could be either positive or negative and that means it is not sufficient
I don't quite understand the explanation any hint that you provide would be very helpful
