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1) is not sufficient say x = -0.5 and n = 3, x^n is not greater than x^(n+1), x = -0.5 and n =4 x^n is greater than x^(n+1)daretodream wrote:If n is a positive integer and x does not equal zero, is x^n > x^(n+1)?
1) x < 1
2) n is even.
daretodream wrote:If n is a positive integer and x does not equal zero, is x^n > x^(n+1)?
1) x < 1
x can be between 0 and 1 or x can be negative
If x is b/w 0 and 1, then x^n > x^(n+1)
if x is negative, x^n > x^(n+1) - here it depends on n
not suff
2) n is even
not suff because no information on x
Together
If x is b/w 0 and 1 and n is even then x^n > x^(n+1)
ex 0.1 -->x^2=0.01
0.1 -->x^2+1=x^3=0.001
0.01>0.001
if x is negative and n is even then x^n > x^(n+1)
ex x=-2-->x^2=4
-2 -->x^2+1=x^3=-8
hence C
for x^n > x^(n+1) , --> 0<x<1daretodream wrote:If n is a positive integer and x does not equal zero, is x^n > x^(n+1)?
1) x < 1
2) n is even.
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