here you go.
x(y+1) will be even under the following conditions :
x - even (y+1)- even
x - odd (y+1)- even
x - even (y+1)- odd
Now from statement 1
x and y are prime numbers
you could pick 2,3 = 2(4) = 8 even
or you could pick 3,2 = 3(3) = 9 odd
Therefore statment 1 is insufficient
From statement 2
It states that Y>7
again you could pick
any 2 numbers for x and y and the product could be even or odd
If you combine the 2 statments,
X and y are prime and y>7.
We know that 2 is the only even prime number and all other prime numbers are odd.
Therefore y+1 will always be even and hence the product x(y+1) will be even whether x is even or odd.
Hope this helps
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