BREAKING: Target Test Prep releases Brand New 2026 On Demand GMAT prep course

Redeem

Target Test Prep · GMAT

Choose how you want to prepare

Learn live with an expert or move at your own pace. Every option includes the complete TTP study system.

★★★★★5.0559 reviews
GMATLiveTeach Starts Oct 17
Chris Peckover, Target Test Prep GMAT expert
LIVE ONLINE CLASSES

Get Ready for GMAT Test Day Faster with Live Online Classes

with Chris Peckover, 100th-Percentile GMAT Scorer

Oct 17 · Chris Peckover
Sat · 11:00 AM to 2:00 PM ET
Oct 20 · Chris Peckover
Tue, Thu · 8:00 to 10:00 PM ET
Oct 25 · Josh Braslow
Sun · 1:00 to 4:00 PM ET
Included
40 hours of live online classes + 6 months of TTP OnDemand
  • Attend the first class for free
  • Every class is recorded, so you never fall behind
View classes & enroll
Limited seats availableTarget Test Prep
EALiveTeachOnDemand 5 seats left Start anytime
EXECUTIVE ASSESSMENT

Target Test Prep EA OnDemand

Self-paced EA prep. Study on your schedule.

Logan Thompson
EXECUTIVE ASSESSMENT

Sep 6 to Dec 6, 2026

with Logan Thompson

165+ EA score guarantee
$05-day trial no automatic billing
Schedule
Sun · 9:30 AM to 12:30 PM ET
Included
40 hours of live online classes plus six months of access to the complete TTP EA OnDemand course.
  • 165+ EA Score Guarantee
  • 4,100+ Quant, Verbal, and Integrated Reasoning practice questions
  • 400+ hours of in-depth video lessons
  • 3,000+ step-by-step video solutions
View EA class & enroll Start free 5-day trial
Limited cohort · enrollment openTrial includes full course accessTarget Test Prep
GMATOnDemand Start anytime
SELF-PACED MASTERCLASS

Target Test Prep GMAT OnDemand

Complete access from day one. Study on your schedule.

715+ score guarantee
$0to start then $127/mo
  • Personalized study plan and analytics
  • Thousands of lessons and practice questions
Start free 5-day trial
Read 559 reviewsTarget Test Prep

Compare the format, schedule, and included access before enrolling. Prices and seat counts shown reflect the supplied offer details.

x an even integer

Expert replies
Post new topic Post Reply
Previous Topic Next Topic
Source: — Data Sufficiency |
User avatar
GMAT Instructor
Posts: 15539
Joined: Tue May 25, 2010 12:04 pmFollowed by: 1906 members
Location: New York, NY
Thanked: 13060 times
GMAT Score:790

by GMATGuruNY » Wed Oct 29, 2014 8:59 am
If x is a positive number, is x an even integer?

(1) 3x is an even integer.

(2) 5x is an even integer.
Statement 1: 3x is even.
It's possible that x = 2, which is an even integer.
It's possible that x = 2/3, which is not an even integer.
INSUFFICIENT.

Statement 2: 5x is even.
It's possible that x = 2, which is an even integer.
It's possible that x = 2/5, which is not an even integer.
INSUFFICIENT.

Statements 1 and 2 combined:
5x-3x = even - even = even.
Since 5x-3x = 2x, 2x is even.
3x-2x = even - even = even.
Since 3x-2x=x, x is even.
SUFFICIENT.

The correct answer is C.
Private tutor exclusively for the GMAT and GRE, with over 20 years of experience.
Followed here and elsewhere by over 1900 test-takers.
I have worked with students based in the US, Australia, Taiwan, China, Tajikistan, Kuwait, Saudi Arabia -- a long list of countries.
My students have been admitted to HBS, CBS, Tuck, Yale, Stern, Fuqua -- a long list of top programs.

As a tutor, I don't simply teach you how I would approach problems.
I unlock the best way for YOU to solve problems.

For more information, please email me (Mitch Hunt) at [email protected].
Student Review #1
Student Review #2
Student Review #3
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Legendary Member
Posts: 510
Joined: Thu Aug 07, 2014 2:24 amFollowed by: 5 members
Thanked: 3 times

by j_shreyans » Wed Oct 29, 2014 9:19 pm
Statements 1 and 2 combined:
5x-3x = even - even = even.
Since 5x-3x = 2x, 2x is even.
3x-2x = even - even = even.
Since 3x-2x=x, x is even.
SUFFICIENT.
Hi Guru ,

Thanks for your reply, but i am unable to understand the combined part..
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
User avatar
GMAT Instructor
Posts: 15539
Joined: Tue May 25, 2010 12:04 pmFollowed by: 1906 members
Location: New York, NY
Thanked: 13060 times
GMAT Score:790

by GMATGuruNY » Thu Oct 30, 2014 2:38 am
j_shreyans wrote:
Statements 1 and 2 combined:
5x-3x = even - even = even.
Since 5x-3x = 2x, 2x is even.
3x-2x = even - even = even.
Since 3x-2x=x, x is even.
SUFFICIENT.
Hi Guru ,

Thanks for your reply, but i am unable to understand the combined part..
When one even integer is subtracted from another even integer, the result is an even integer.
In math terms:
even - even = even.

Statement 1: 3x is even
Statement 2: 5x is even

Since 5x is even and 3x is even, their difference -- 2x -- is also even.
Since 3x is even and 2x is even, their difference -- x -- is also even.

Thus, the two statements combined imply that x is an even integer.
Private tutor exclusively for the GMAT and GRE, with over 20 years of experience.
Followed here and elsewhere by over 1900 test-takers.
I have worked with students based in the US, Australia, Taiwan, China, Tajikistan, Kuwait, Saudi Arabia -- a long list of countries.
My students have been admitted to HBS, CBS, Tuck, Yale, Stern, Fuqua -- a long list of top programs.

As a tutor, I don't simply teach you how I would approach problems.
I unlock the best way for YOU to solve problems.

For more information, please email me (Mitch Hunt) at [email protected].
Student Review #1
Student Review #2
Student Review #3
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY

GMAT/MBA Expert

User avatar
Elite Legendary Member
Posts: 10392
Joined: Sun Jun 23, 2013 6:38 pmFollowed by: 511 members
Location: Palo Alto, CA
Thanked: 2867 times
GMAT Score:800

by [email protected] » Thu Oct 30, 2014 9:29 pm
Hi j_shreyans,

Mitch's explanation shows the value of knowing your Number Property rules. In the event that you don't spot that pattern (when it's there), you can still "discover" the pattern by TESTing VALUES. Here's how....

Once you've determined that Fact 1 is INSUFFICIENT and Fact 2 is INSUFFICIENT, you combine Facts....

3X is an EVEN integer
5X is an EVEN integer

We're told that X is a POSITIVE number. Let's list out values for each Fact and see if a pattern emerges....

3X = EVEN integer.....X COULD be 2/3, 4/3, 6/3 = 2, 8/3, 10/3, 12/3 = 4, etc.

5X = EVEN integer.....X COULD BE 2/5, 4/5, 6/5, 8/5, 10/5 = 2, 12/5, 14/5, 16/5, 18/5, 20/5 = 4, etc.

Since the denominators will always be 3 (for the first group) and 5 (for the second group), most values of X will not fit both Facts. However, the ones that DO fit both Facts (that we can immediately see) are 2 and 4. If we increase the lists, that pattern will continue....6, 8, 10, etc. This provides the proof that X is ALWAYS going to be an EVEN integer, so the answer to the question is ALWAYS YES.

Final Answer: C

GMAT assassins aren't born, they're made,
Rich[/b]
Contact Rich at [email protected]
Image
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY

GMAT/MBA Expert

User avatar
GMAT Instructor
Posts: 16207
Joined: Mon Dec 08, 2008 6:26 pmFollowed by: 1268 members
Location: Vancouver, BC
Thanked: 5254 times
GMAT Score:770

by Brent@GMATPrepNow » Fri Oct 31, 2014 8:04 am
j_shreyans wrote:If x is a positive number, is x an even integer?

(1) 3x is an even integer.

(2) 5x is an even integer.
Target question: Is x an even integer?

Statement 1: 3x is an even integer
There are two possible cases that satisfy this condition:
Case a: x is an even integer
Case b: x is a fraction with 3 in the denominator and an even number in the numerator. For example, x COULD equal 2/3 or 4/3 or 8/3, or 10/3, etc). In this case x is NOT an even integer
Since we cannot answer the target question with certainty, statement 1 is NOT SUFFICIENT

Statement 2: 5x is an even integer
There are two possible cases that satisfy this condition:
Case a: x is an even integer
Case b: x is a fraction with 5 in the denominator and an even number in the numerator. For example, x COULD equal 2/5 or 4/5 or 6/5, or 8/5, etc). In this case x is NOT an even integer
Since we cannot answer the target question with certainty, statement 2 is NOT SUFFICIENT

Statements 1 and 2 combined
Statement 1 tells us that x is EITHER an even integer OR a fraction with 3 in the denominator
Statement 2 tells us that x is EITHER an even integer OR a fraction with 5 in the denominator
Since both statements are true, it must be the case that x is an even integer
Since we can answer the target question with certainty, the combined statements are SUFFICIENT

Answer = C

Cheers,
Brent
Brent Hanneson - Creator of GMATPrepNow.com
Image
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
GMAT Instructor
Posts: 2630
Joined: Wed Sep 12, 2012 3:32 pmFollowed by: 119 members
Location: East Bay all the way
Thanked: 625 times
GMAT Score:780

by Matt@VeritasPrep » Fri Oct 31, 2014 10:29 am
Here's an algebraic approach.

S1 tells us that x = m/3, where m is an even integer
S2 tells us that x = n/5, where n is an even integer

Clearly neither statement alone is sufficient. Together, we have x = m/3 and x = n/5, so we know that m/3 = n/5, or 3n = 5m. This tells us that m is a multiple of 3 and that n is a multiple of 5.

Hence x = m/3 = (multiple of 3)/3 = integer and x = n/5 = (multiple of 5)/5 = integer, and we know that x must be an integer.
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Post new topic Post Reply
• Page 1 of 1