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kulksnikhil
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x^3>y?
Source: Beat The GMAT — Data Sufficiency |
Since no information on value of X and Y. X,Y = { Real Number, i.e -Root n,-n,-m/n,0,m/n,Root n,n }
is X^3 > Y
1.Root (X) > Y
When X and Y are Positive Integer +n , X^3 > Y == True
X is m/n then
if X=1/4 , Y= 1/8
Root (X) = 1/2 > 1/8 > Y
But X^3 = (1/4)^3 < Y Hence False
2. X > Y
again the same
When X and Y are Positive Integer +n , X^3 > Y == True
X is m/n then
if X=1/4 , Y= 1/8
But X^3 = (1/4)^3 < Y Hence False
3. (1) and (2) X > Y and Root(X) > Y
if ( X,Y are Positive Integer then True)
If ( X,Y are Rationale No, i.e m/n then maybe false)
Ans.E
is X^3 > Y
1.Root (X) > Y
When X and Y are Positive Integer +n , X^3 > Y == True
X is m/n then
if X=1/4 , Y= 1/8
Root (X) = 1/2 > 1/8 > Y
But X^3 = (1/4)^3 < Y Hence False
2. X > Y
again the same
When X and Y are Positive Integer +n , X^3 > Y == True
X is m/n then
if X=1/4 , Y= 1/8
But X^3 = (1/4)^3 < Y Hence False
3. (1) and (2) X > Y and Root(X) > Y
if ( X,Y are Positive Integer then True)
If ( X,Y are Rationale No, i.e m/n then maybe false)
Ans.E
