Is x = 0? 1) 3x = 2xy 2) (x^2) = x ---------- IMO [spoiler](C)[/spoiler] 1) 3x = 2xy 3x - 2xy = 0 x (3-2y) = 0 x = 0 OR 3-2y = 0 2)(x^2) = x x = 0 OR x = 1 3)Combining 1 and 2: x must be 0

Woops! wrong forum, should be moved to DS Section.

Should this answer not be A alone becuase 3x - 2xy = 0 then x(3-2Y) = 0 then X=0 and y = 3/2 so sufficent how can it be C

Is x = 0? 1) 3x = 2xy 2) (x^2) = x It does not personally bother me that you posted this question in the "wrong" forum, because we're still talking about math stuff here:) However, please make sure that you include the source whenever you post a question. Also, it would be good to include the OA using the spoiler tag. Now to the question: Is x=0 ? Statement 1: 3x=2xy if y=1.5 then x could be any value, including zero. Insufficient. Statement 2: x²=x This is true for x=0 and x=1. Insufficient. Combining the statements: x=0 would make both statements correct. x=1 could also make both statements correct, because: 3(1)=2(1)*y, is true if y=1.5 Insufficent. [spoiler] The answer is E.[/spoiler]

venmic wrote:Should this answer not be A alone becuase 3x - 2xy = 0 then x(3-2Y) = 0 then X=0 and y = 3/2 so sufficent how can it be C That's actually not true. Although your rearrangement was correct, the conclusion drawn from it (X=0 and y = 3/2) was not. For a product to equal zero, it is ENOUGH when ONE of the factors is equal to zero. Thus, the proper conclusion is X=0 OR y = 3/2.

venmic wrote:Should this answer not be A alone becuase 3x - 2xy = 0 then x(3-2Y) = 0 then X=0 and y = 3/2 so sufficent how can it be C The solution for the equation: x(3-2Y) = 0, cannot be just x=0 AND y=3/2. It is actually, either x=0 or y=3/2 or both (x=0 and y=3/2)

This is tricky I blindly choose C because both 1) and 2) stated x = 0 So the lesson here is that we should consider all values given by the statements and combine them? 1) x = 0 OR y = 3/2 2) x = 0 OR x = 1 3)Combined: x = 0 AND y = 3/2 x = 1 AND y = 3/2 What's the best method to tackle this type of questions?

MAAJ wrote:Is x = 0? 1) 3x = 2xy 2) (x^2) = x ---------- IMO [spoiler](C)[/spoiler] 1) 3x = 2xy 3x - 2xy = 0 x (3-2y) = 0 x = 0 OR 3-2y = 0 2)(x^2) = x x = 0 OR x = 1 3)Combining 1 and 2: x must be 0 3x = 2xy Can be written as 3 = 2y { Cancelling X from both sides } Now y = 3/2 (x^2) = x Can be written as x = 1 { Cancelling X from both sides } So to my knowledge none of them is sufficient to reach the conclusion x = 0.

Abhishek009, the second statement is a quadratic equation, so you should not solve it dividing by a variable because you could miss an answer. x² = x x² - x + 0 = 0 (x-1)(x-0) = 0 x = 1 OR x = 0 x = 0 is a possible solution to the equation! Abhishek009 wrote: 3x = 2xy Can be written as 3 = 2y { Cancelling X from both sides } Now y = 3/2 (x^2) = x Can be written as x = 1 { Cancelling X from both sides } So to my knowledge none of them is sufficient to reach the conclusion x = 0.