Ashok and Mohan can do a piece of work in 12 days Mohan and Binod and do the same work in 15 days If Ashok is twice as good a workman as Binod is, In how much time will Mohan complete the work alone Thank You

gmat7202011 wrote:Ashok and Mohan can do a piece of work in 12 days Mohan and Binod and do the same work in 15 days If Ashok is twice as good a workman as Binod is, In how much time will Mohan complete the work alone Thank You A+M=1/12 M+B=1/15 A=2B; M-? A=1/12-M; B=A/2; M+(1/12-M)/2=1/15 --> 30M+15/12-15M=2 --> 15M=9/12 --> M=9/(12*15)=1/20 Mohan will complete work in 20 days alone

gmat7202011 wrote:Ashok and Mohan can do a piece of work in 12 days Mohan and Binod and do the same work in 15 days If Ashok is twice as good a workman as Binod is, In how much time will Mohan complete the work alone In one day, Ashok's work = 2*(Binod's work) In one day, Ashok and Mohan can do 1/12 of the whole work, i.e. 2*(Binod) and Mohan can do 1/12 of the whole work. ...... (i) In one day, Binod and Mohan can do 1/15 of the whole world. ....... (ii) Subtracting (ii) from (i), In one day, Binod can do (1/12 - 1/15) = 1/60 of the work ....... (iii) Subtracting (iii) from (ii), In one day, Mohan can do (1/15 - 1/60) = 3/60 = 1/20 of the whole work Therefore, Mohan will complete the work in 20 days.

gmat7202011 wrote:Ashok and Mohan can do a piece of work in 12 days Mohan and Binod and do the same work in 15 days If Ashok is twice as good a workman as Binod is, In how much time will Mohan complete the work alone Thank You Plug in work = 60. Combined rate for A+M = work/time = 60/12 = 5 units per day. Combined rate for M+B = work/time = 60/15 = 4 units per day. Subtracting, we get (A+M) - (M+B) = A-B = 5-4 = 1 unit per day. Since A's work is twice as good, A=2B. Substituting A=2B into A-B = 1, we get: 2B-B = 1. B=1. Substituting B=1 into M+B = 4 units per day, we get: M+1 = 4. M = 3 units per day. Time for M = work/rate = 60/3 = 20 days.

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