Let A = fraction of job that Machine A can complete in 1 hour
Let B = fraction of job that Machine B can complete in 1 hour
Let C = fraction of job that Machine C can complete in 1 hour
15 A Machines and 7 B Machines take 4 hours to complete job
So, in 1 hour, 15 A Machines and 7 B Machines will complete 1/4 of job
In other words, 15A + 7B = 1/4 of job
8 B Machines and 15 C Machines take 11 hours to complete job
So, in 1 hour, 8 B Machines and 15 C Machines will complete 1/11 of job
In other words, 8B + 15C = 1/11 of job
If BOTH GROUPS WORK TOGETHER, we see that, in 1 hour, (15 A Machines and 7 B Machines) + (8 B Machines and 15 C Machines) will complete (1/4 + 1/11) of job
In other words, add 15A + 7B = 1/4 of job and 8B + 15C = 1/11 of job, to get: 15A + 15B + 15C = 15/44
This means that, in 1 hour, 15 A Machines, 15 B Machines, and 15 C Machines can complete 15/44 of the job.
Divide both sides by 15 to get A + B + C = 1/44
This means that, in 1 hour, 1 A Machine, 1 B Machine, and 1 C Machine can complete 1/44 of the job.
So, it will take 44 hours for 1 A Machine, 1 B Machine, and 1 C Machine to complete the job.
Answer: C
Cheers,
Brent
Brent Hanneson - Creator of GMATPrepNow.com
