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by MI3 » Mon May 23, 2011 9:14 pm
Q. Lindsay can paint 1/x of a certain room in 20 minutes. What fraction of the same room can Joseph paint in 20 minutes if the two of them can paint the room in an hour, working together at their respective rates?
A. 1/3x
B. 3x/(x – 3)
C. (x – 3) / 3x
D. x / (x – 3)
E. (x – 3) / x

Ans - C[/spoiler]
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by Anurag@Gurome » Mon May 23, 2011 9:48 pm
MI3 wrote:Q. Lindsay can paint 1/x of a certain room in 20 minutes. What fraction of the same room can Joseph paint in 20 minutes if the two of them can paint the room in an hour, working together at their respective rates?
A. 1/3x
B. 3x/(x – 3)
C. (x – 3) / 3x
D. x / (x – 3)
E. (x – 3) / x

Ans - C[/spoiler]
Lindsay can paint 1/x of a certain room in 20 minutes implies (1/x) ÷ 20 = 1/20x
Let John can paint 1/F of the room in 20 minutes.
Then 1/20x + 1/20F = 1/60
1/x + 1/F = 1/3
1/F = 1/3 - 1/x = (x - 3)/3x

The correct answer is C.
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by MI3 » Mon May 23, 2011 9:55 pm
Hello Anurag,

Thank you for getting back to me, but would you also mind clarifying the following: 1/20x and 1/20F would be the "rate" of work for Lindsay and John respectively, so I don't get how you have formed the third equation of > 1/20x + 1/20F = 1/60.

W = R * T

So in this case, how is the rate getting equated to (presumably) the time?
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by Anurag@Gurome » Mon May 23, 2011 9:59 pm
MI3 wrote:Hello Anurag,

Thank you for getting back to me, but would you also mind clarifying the following: 1/20x and 1/20F would be the "rate" of work for Lindsay and John respectively, so I don't get how you have formed the third equation of > 1/20x + 1/20F = 1/60.

W = R * T

So in this case, how is the rate getting equated to (presumably) the time?
1/20x is the work done by Lindsay in 1 minute and 1/20F is the work done by John in 1 minute.
So, 1 minute work by Lindsay + John = 1/20x + 1/20F, which is equal to 1/60 (As 1 hr = 60 minutes)
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by GMATGuruNY » Tue May 24, 2011 2:58 am
MI3 wrote:Q. Lindsay can paint 1/x of a certain room in 20 minutes. What fraction of the same room can Joseph paint in 20 minutes if the two of them can paint the room in an hour, working together at their respective rates?
A. 1/3x
B. 3x/(x – 3)
C. (x – 3) / 3x
D. x / (x – 3)
E. (x – 3) / x

Ans - C[/spoiler]
Let job = 30 units, let x=5.
In 20 minutes, Lindsay produces (1/x)*30= (1/5)*30 = 6 units.
Thus, in 60 minutes, Lindsay produces 3*6 = 18 units.
Since the job is completed in an hour, work produced by Joseph = 30-18 = 12 units.
Thus, in 20 minutes -- 1/3 the time -- Joseph completes (1/3)*12 = 4 units.
Fraction of the job completed by Joseph in 20 minutes = 4/30 = 2/15. This is our target.

Now we plug x=5 into the answers to see which yields our target of 2/15.

Only answer choice C works:
(x-3)/3x = (5-3)/(3*5) = 2/15.

The correct answer is C.
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by MI3 » Tue May 24, 2011 10:57 am
Understood. Thank you.
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by djiddish98 » Tue May 24, 2011 1:38 pm
Anurag@Gurome wrote: 1/F = 1/3 - 1/x = (x - 3)/3x
Dumb question - How did you get from 1/3 - 1/x to (x-3)/3x? I can see that the results are equal (x/3x = 1/3 and 3/3x = 1/x), but I can't arithmetically get there.

Edit: Nevermind I got it.

1/F = 1/3 - 1/x -> x/f = x/3-1 -> 3x/f = x-3 -> 1/f = (x-3)/3x.

The tricky part is that we need to solve for 1/F, not F. I kept getting the inverse as the answer before I realized that
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