Work problem
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- sureshbala
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If money charged by M is 6 $, then money charged by P and K will 2$ and 1$ respectively.
Since the money is divided in the ratio of the work contributed by them, the work contributed by M, P and K is in the ratio 6:2:1.
So the time charged by M is 6/9 x(162) and by K is 1/9(162).
Hence the difference = 5/9(162) = 90 hrs
Since the money is divided in the ratio of the work contributed by them, the work contributed by M, P and K is in the ratio 6:2:1.
So the time charged by M is 6/9 x(162) and by K is 1/9(162).
Hence the difference = 5/9(162) = 90 hrs