II wrote:See attached problem.
Interested in seeing the different approaches in solving this question.

Thanks in advance.
II

Both Statements 1 & 2 alone are insufficient to answer the question and taken together they still don't offer the value for n. Hence, I chose E.

I think the answer should be B

mandy12 wrote:I think the answer should be B

What does "meet the schedule" mean from statement 2? If it means "complete the order", then I think the answer is C. If it means, get back to the rate in which is needed to complete the order, I think it's E... I think it means "complete the order", so I'd say the answer is C, which makes me hesitant because it seems to be too obvious, but here's my logic: we know from the stem that it's going to take an average rate of 1000 tools/day and we're asked for the total number or days, n, to complete the order. Because we know that they're not going to give us n directly, we need to find the work (w) for the equation: rate x time= work. Looking at the statments:

1. ok, we're given the rate time and work for the first five days: 600 tools/day for 5 days. So, 3000 tools total. Can't do anything with that.

2. We know that to "meet the schedule" which I take to mean "complete the order", the manufacturer had to crank it up to 1,500 tools/day for the last 4 days. So, the last four days, there were 6000 tools produced. I initially thought this info would be sufficient to answer the question. However, there are a number of combinations of different rates over different periods of time that we average with the rate and work for what's given in statement 2 to get to 1000 tools/day. Because of that, there's more than one answer and 2 is insufficient.

1&2 together: If we know what it took to complete the order from statement 2, then we can plug statement 1 in to the average RTW matrix to get the total number of days, n, which is 9.

I'd love to hear other's thoughts on this one. I'm definitely overthinking it.

What is the OA ??

Thanks
-Vittal

IMO B

here stem 2 provides us information that due to problem, last 4 days production was 1500*4=6000 units. if the schedule was 1000 units per day, even though 2 days there was no production, the target of 6 days is met by production in last 4 days.

what's tha OA?

Ans should be E as there is no way to figure out n.

It could be that first 5 days there were problem then 10 days it went smooth at 1000 per day and then last 4 days they had to catch up with 1500 per day.

netigen wrote:Ans should be E as there is no way to figure out n.

It could be that first 5 days there were problem then 10 days it went smooth at 1000 per day and then last 4 days they had to catch up with 1500 per day.

1000 tools --> 1 day
(1000 * n) tools --> n days

Stmt-I
Prod. Problems:
600 tools --> 1 day
(600 * 5) = 3000 tools <-- first 5 days

what about (n-5) days? No information given on that.

Insuff

Stmt-II
Prod Problems:
1500 tools --> 1 day
(1500 * 4) = 6000 tools <-- last 4 days

what about (n-4) days?
Insuff

Stmt-I & Stmt-II:
First 5 days --> 3000 tools
Last 4 days --> 6000 tools
n days ---> (1000 * n) tools.

No way of determining the total number of days.
Insuff

OA [spoiler][E][/spoiler]

yeah E for me as well as there is no way to find out the total days from the given info.