Live GMAT classes with Target Test Prep start Nov 21 and Nov 22. First class free.

See classes
Target Test Prep · GMAT

Choose how you want to prepare

Learn live with an expert or move at your own pace. Every option includes the complete TTP study system.

Newsweek Readers’ Choice Awards 2026 winner: Target Test Prep, #1 Test Prep

Target Test Prep was voted #1 Best Test Prep in the 2026 Newsweek Readers’ Choice™ Awards.

★★★★★5.0563 reviews
GMATLiveTeachStarts Nov 22
Josh Braslow, Target Test Prep GMAT expert
LIVE ONLINE CLASSES

Get Ready for GMAT Test Day Faster with Live Online Classes

with Josh Braslow, 20+ years in test prep

Nov 22 · Josh Braslow
Sun · 9:30 AM to 12:30 PM ET
Included
40 hours of live online classes + 6 months of TTP OnDemand
  • Attend the first class for free
  • Every class is recorded, so you never fall behind
View classes & enroll
Limited seats availableTarget Test Prep
EALiveTeachOnDemandStart anytime
EXECUTIVE ASSESSMENT

Target Test Prep EA OnDemand

Self-paced EA prep. Study on your schedule.

EXECUTIVE ASSESSMENT

with

165+ EA score guarantee
$05-day trial no automatic billing
Schedule
Included
40 hours of live online classes plus six months of access to the complete TTP EA OnDemand course.
  • 165+ EA Score Guarantee
  • 4,100+ Quant, Verbal, and Integrated Reasoning practice questions
  • 400+ hours of in-depth video lessons
  • 3,000+ step-by-step video solutions
View EA class & enroll Start free 5-day trial
Limited cohort · enrollment openTrial includes full course accessTarget Test Prep
GMATOnDemandStart anytime
SELF-PACED MASTERCLASS

Target Test Prep GMAT OnDemand

Complete access from day one. Study on your schedule.

715+ score guarantee
$0to start then $127/mo
  • Personalized study plan and analytics
  • Thousands of lessons and practice questions

Word T -- Help!!!

Expert replies
by ramonsa » Thu May 07, 2009 11:46 am
Hello ... need some help to see this problem.

There are 26 students who have read a total of 56 books among them. The only books they have read, though, are Aye,Bee,Cod, and Dee. If 10 students have only read Aye, and 8 students have read only Cod and Dee, what is the smallest number of books any of remaining students could have read?

Thanks
Ramon
Join the discussion
Source: — Problem Solving |

by stevestein » Thu May 07, 2009 1:02 pm
Among the 26 students total, we have solid information about the reading accomplishments of 18 of the students:

10 students have each read exactly one book = 10 books read.
8 students have read exactly two books = 16 books read.

At this point, we know that 26 books (26 out of 50 total books) have been read by those 18 kids (18 out of 26 kids).

This means that the 8 remaining students must read the 30 remaining books.

What is the smallest number that any of these students could read?

If we wish to minimize the number of books read by one of these remaining students, we should maximize the number of books read by the others.

So, if 7 of the remaining 8 students read all 4 books, that gives us a total of 28 books between them, leaving 2 books to be read by the last remaining student.

Thus, 2 is the minimum number of books that could be read by any of the remaining students.

I hope that's helpful! Let me know.
Steve Stein
PowerScore GMAT Instructor
Join the discussion