Gurpinder wrote:hi vineesh,
i wanted to clarify something. so the best method for these kind of problems is to have 1 equation for the total and 1 equation of the relationship and then substitute?
Hi Gurpinder,
I thought I'd jump in here.
The "best" approach here really depends on how comfortable you are with systems of equations. Also, note that you can use the elimination method when solving systems of equations.
Alternatively, you can solve this equation using 1 variable.
Since we're trying to find the number of pies that Alfred cooked, let's let
A = the number of pies that
Alfred cooked
Since there were 49 pies cooked altogether, we can say that
49-A = the number of pies that
Nick cooked
Next we are told that:
twice the number of pies that alfred cooked was 14 pies more than the number of pies that nick cooked
So, we can write 2
A =
49-A + 14
From here, we have an equation that we can solve for A
2A = 49-A+14
2A = 63-A
3A = 63
A=21
Brent Hanneson - Creator of GMATPrepNow.com
