word problem

Let's try to put this into an equation:

c+12 = 2r is r>c
A r>5 gives us nothing, since it is possible that
r=6 c=0 c+12=2r 12=12 but it is also possible that
r=15 c=18 so 18+12=2*15

B tells us that c<12 so (less than 12)+12=2r
Were c=12 we would have 12+12=r+r or c=r. However, since c is less than 12, we know it has to be less that r.
We can also look at this as an average question.
(c+12)/2 is the average, or r. We know that since c is less than 12, the average of c and 12 must be somewhere between the two, less than 12 but more than c. Therefore, r must be greater than c and answer B is sufficient.

Thankyou for the reply ...the question seems much easier now

Thankyou for the reply ...the question seems much easier now

another approach ...

According to the que: c + 12 = 2r --- (1)
Question is asking: c < r ? --- (2)

From (1) & (2): c < c/2 + 6
or c < 12 ?

Stmt1 : insuff

Stmt2 : c < 12

Therefore B is suff