Ankitaverma wrote:If it is 6:27 in the evening on a certain day, what time in the morning was it exactly 2,880,717 minutes earlier? (Assume standard time in one location.)
(A) 6:22
(B) 6:24
(C) 6:27
(D) 6:30
(E) 6:32

q/a-d

The number of minutes in each 24-hour period = 24*60 = 1440.
Thus, every time the clock turns back a number of minutes that is a multiple of 1440, the clock turns back a FULL DAY, so that the time will be the same as it is now:
6:27pm.

1440*2 = 2880.
Since 2,880,000 is a multiple of 1440, the time 2,880,000 minutes ago was the same as it is now:
6:27pm.

We need to determine the time when the clock turns back another 717 minutes.
The number of minutes in a 12-hour period = 1/2 * 1440 = 720.
Thus, 720 minutes ago -- in other words, 12 hours ago -- the time was 6:27am.
Thus, 717 minutes ago -- 3 minutes LESS than a full 12 hours ago -- the time was 6:30am.

The correct answer is D.

2880717 divided by 60 = 48011 hours and 57 minutes
48011 divided by 24 = 2000 days and 11 hours

Looking at the remainders: 11 hours and 57 minutes earlier than 6:27 is 6.30 am

answer D

1 day = 24 hrs = 24*60 = 1440 hrs.

So, divinding 2880717/1440 we find 288000 is exactly 20*1440 so 20 days earlier same time 6:27 in evening.

Now for remaining 717 minutes its exactly 12 hrs back but with 3 minutes added to it.

so 12 hrs back is 6:27 in morning now adding 3 minutes to it is 6:30 in the morning.

ans: D

Ankitaverma wrote:If it is 6:27 in the evening on a certain day, what time in the morning was it exactly 2,880,717 minutes earlier? (Assume standard time in one location.)
(A) 6:22
(B) 6:24
(C) 6:27
(D) 6:30
(E) 6:32

q/a-d

I remember solving this in one of either Mahattan or Veritas tests. I just subtracted the units place of '27' and '2880717'. The units digit of the resultant figure had to be '0'. Only D fulfills that. Chose D.