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Wire Cut into 2 Pieces

Problem Solving — algebra and arithmetic
Expert replies
by rapper » Mon Oct 22, 2012 4:16 pm
Q1:

A thin piece of wire 40 meters long is cut into two pieces. One piece is used to form a

circle with radius r, and the other is used to form a square. No wire is left over. Which

of the following represents the total area, in square meters, of the circular and the square

regions in terms of r?

A. (pi)r2

B. (pi)r2 + 10

C. (pi)r2 + ¼ (pi)^2r^2

D. (pi)r2 + (40-2pr)^2

E. (pi)r2 + (10- ½ (pi)r)^2

Hi i Solved it and got answer D.I dont have its answer,so can anyone help
and let me know is it correct ?
Join the discussion
Source: — Quantitative Reasoning |

by \'manpreet singh » Mon Oct 22, 2012 7:44 pm
rapper wrote:Q1:

A thin piece of wire 40 meters long is cut into two pieces. One piece is used to form a

circle with radius r, and the other is used to form a square. No wire is left over. Which

of the following represents the total area, in square meters, of the circular and the square

regions in terms of r?

A. (pi)r2

B. (pi)r2 + 10

C. (pi)r2 + ¼ (pi)^2r^2

D. (pi)r2 + (40-2pr)^2

E. (pi)r2 + (10- ½ (pi)r)^2

Hi i Solved it and got answer D.I dont have its answer,so can anyone help
and let me know is it correct ?
Yes the answer is E

Since circle is radius r, therefore the length of the wire forming circle is 2(pi)r

rest of the length 40- 2(pi)r is length of wire forming the square.

Area of circle is (pi)r2

Area of square is 1/2(40-pr)^2=(10- ½ (pi)r)^2

Total area= (pi)r2 + (10- ½ (pi)r)^2 voila!

=======================================
Singh

If you like the post take time to click "thanks" button :)

There is only one success--to be able to spend your life in your own way.
Last edited by \'manpreet singh on Wed Oct 24, 2012 8:50 pm, edited 2 times in total.
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by Brent@GMATPrepNow » Tue Oct 23, 2012 6:11 am
rapper wrote:Q1:

A thin piece of wire 40 meters long is cut into two pieces. One piece is used to form a

circle with radius r, and the other is used to form a square. No wire is left over. Which

of the following represents the total area, in square meters, of the circular and the square

regions in terms of r?

A. (pi)r^2

B. (pi)r^2 + 10

C. (pi)r^2 + ¼ (pi)^2r^2

D. (pi)r^2 + (40-2pr)^2

E. (pi)r^2 + (10- ½ (pi)r)^2

Hi i Solved it and got answer D.I dont have its answer,so can anyone help
and let me know is it correct ?

The correct answer is actually E

Since r is the radius of the circle, the area of the circle will be πr^2.
If r is the radius of the circle, the length of wire used for this circle will equal its circumference which is 2πr

So, the length of wire to be used for the square must equal 40 - 2πr

In other words, the perimeter of the square will be 40 - 2πr

Since squares have 4 equal sides, the length of each side of the square will be (40 - 2πr )/4, which simplifies to be 10 - πr/2

If each side of the square has length 10 - πr/2, the area of the square will be (10 - πr/2)^2

So, the total area will equal πr^2 + (10 - πr/2)^2, which is the same as E

Cheers,
Brent
Brent Hanneson - Creator of GMATPrepNow.com
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by Brent@GMATPrepNow » Tue Oct 23, 2012 6:22 am
'manpreet singh wrote:
rapper wrote:Q1:

A thin piece of wire 40 meters long is cut into two pieces. One piece is used to form a

circle with radius r, and the other is used to form a square. No wire is left over. Which

of the following represents the total area, in square meters, of the circular and the square

regions in terms of r?

A. (pi)r2

B. (pi)r2 + 10

C. (pi)r2 + ¼ (pi)^2r^2

D. (pi)r2 + (40-2pr)^2

E. (pi)r2 + (10- ½ (pi)r)^2

Hi i Solved it and got answer D.I dont have its answer,so can anyone help
and let me know is it correct ?
Yes the answer is D

Since circle is radius r, therefore the length of the wire forming circle is 2(pi)r

rest of the length 40- 2(pi)r is length of wire forming the square.

Area of circle is (pi)r2

Area of square is (40-2pr)^2

Total area= pi)r2 + (40-2pr)^2 voila!
There's a small problem with the part in blue (above)
40- 2(pi)r represents the entire perimeter of the square.
Before we can find the area, we must find the length of each side. To do so, we need to divide 40- 2(pi)r by 4

Cheers,
Brent
Brent Hanneson - Creator of GMATPrepNow.com
Image
Join the discussion

by \'manpreet singh » Wed Oct 24, 2012 8:46 pm
Brent@GMATPrepNow wrote:
'manpreet singh wrote:
rapper wrote:Q1:

A thin piece of wire 40 meters long is cut into two pieces. One piece is used to form a

circle with radius r, and the other is used to form a square. No wire is left over. Which

of the following represents the total area, in square meters, of the circular and the square

regions in terms of r?

A. (pi)r2

B. (pi)r2 + 10

C. (pi)r2 + ¼ (pi)^2r^2

D. (pi)r2 + (40-2pr)^2

E. (pi)r2 + (10- ½ (pi)r)^2

Hi i Solved it and got answer D.I dont have its answer,so can anyone help
and let me know is it correct ?
Yes the answer is D

Since circle is radius r, therefore the length of the wire forming circle is 2(pi)r

rest of the length 40- 2(pi)r is length of wire forming the square.

Area of circle is (pi)r2

Area of square is (40-2pr)^2

Total area= pi)r2 + (40-2pr)^2 voila!
There's a small problem with the part in blue (above)
40- 2(pi)r represents the entire perimeter of the square.
Before we can find the area, we must find the length of each side. To do so, we need to divide 40- 2(pi)r by 4



Yes Brent you are right , thanks for the correction! :) I have edited the answer now
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