BREAKING: Target Test Prep releases Brand New 2026 On Demand GMAT prep course

Redeem
TTP OnDemand GMAT Video Course
Featured Course

Target Test Prep GMAT OnDemand

Scott Woodbury-Stewart’s private virtual classroom — 400 hours of master-class video lessons for the GMAT Focus Edition.

  • 715+ score guarantee — highest in the industry (99th percentile)
  • 52 chapters · 1,500+ lessons · 4,000+ practice questions
  • 400 hours of video · 1,500+ instructor-led HD smartboard lessons
  • 300,000+ students accepted to Harvard, Stanford, Wharton, Booth & Sloan & more
  • 24/7 live support + weekly Zoom office hours with GMAT instructors
  • TTP AI Assist — 24/7 AI-powered virtual tutor for instant help
  • 1,200+ flashcards + AI-powered study assistant & daily calendar
  • OnDemand, LiveTeach & GMAT Bootcamp formats available
  • Also: GRE, SAT Math & Executive Assessment courses
  • MBA Admissions Consulting now available
  • 🏆 2025 EdTech Breakthrough Award: Test Prep Solution Provider of the Year
  • 200,000+ students served
  • 5-day free trial — $0 to start, no auto-billing, cancel anytime
★★★★★ 5.0 (559 reviews)
130-pt guarantee
$0 to start then $127/mo
Start Free 5-Day Trial Read 559 Reviews →

While person A walked 200m, person B walked 100m. They walk

Expert replies
Post new topic Post Reply
Previous Topic Next Topic
User avatar
Elite Legendary Member
Posts: 3991
Joined: Fri Jul 24, 2015 2:28 amFollowed by: 37 members
Location: Las Vegas, USA
Thanked: 19 times
by Max@Math Revolution » Fri Dec 06, 2019 12:00 am
[GMAT math practice question]

While person A walked 200m, person B walked 100m. They walked facing each other for a distance of 1500m and met in 10 minutes. Find the sum of the distances persons A and B walked in 1 minute.

A. 100m
B. 120m
C. 150m
D. 160m
E. 170m
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Source: — Data Sufficiency |
Senior | Next Rank: 100 Posts
Posts: 30
Joined: Thu Oct 11, 2018 9:10 am

by nitink » Fri Dec 06, 2019 2:42 am
a - Speed of A
b - Speed of B

Since they walked towards each other, their relative speed is a + b.
Speed = Distance /Time
Given a +b = 1500 / 10 m/ minute

a+ b =150.............................(1)

Also, Given a/b = 200 /100
a = 2b

Put this in Equation (1) to solve for a and b

a= 100 m/ min

b = 50 m/min

So , distance traveled in one minute = 50 +100 =150 m

Ans C
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
User avatar
Elite Legendary Member
Posts: 3991
Joined: Fri Jul 24, 2015 2:28 amFollowed by: 37 members
Location: Las Vegas, USA
Thanked: 19 times

by Max@Math Revolution » Sun Dec 08, 2019 5:16 pm
=>

Assume Va and Vb are the speeds of persons A and B, respectively.

Then we have Va = 2Vb and 10Va + 10Vb = 10(2Vb) + 10Vb = 20Vb + 10Vb = 30Vb = 1500, and Vb = 50m/min. Then Va = 2Vb = 2(50) = 100m/min.

Then the distances walked by persons A and B in 1 minute are 100m and 50m, respectively. So, the total distance = 100 + 50 = 150.

Therefore, C is the answer.
Answer: C
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Post new topic Post Reply
• Page 1 of 1