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Which of the following is equivalent to \(\dfrac{8!+9!}{10!}?\)

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by Vincen » Tue Oct 06, 2020 7:19 am
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Which of the following is equivalent to \(\dfrac{8!+9!}{10!}?\)

A. \(\dfrac1{72}\)

B. \(\dfrac9{100}\)

C. \(\dfrac19\)

D. \(\dfrac9{10}\)

E. \(\dfrac{17}{10}\)

Answer: C

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Re: Which of the following is equivalent to \(\dfrac{8!+9!}{10!}?\)

by Scott@TargetTestPrep » Sat Oct 10, 2020 2:26 pm
Vincen wrote: ↑
Tue Oct 06, 2020 7:19 am
 Which of the following is equivalent to \(\dfrac{8!+9!}{10!}?\)

A. \(\dfrac1{72}\)

B. \(\dfrac9{100}\)

C. \(\dfrac19\)

D. \(\dfrac9{10}\)

E. \(\dfrac{17}{10}\)

Answer: C

Solution:

Factoring out 8! from the numerator and denominator, we have:

8!(1 + 9) / [8!(9 x 10)]

After canceling 8! from the numerator and denominator, we have:

(1 + 9) / (9 x 10) = 10/90 = 1/9

Answer: C

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