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When positive integer k is divided by 5, the remainder is 2. When k is divided by 6, the remainder is 5. If k is less

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by BTGmoderatorDC » Fri Jun 11, 2021 7:58 pm

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When positive integer k is divided by 5, the remainder is 2. When k is divided by 6, the remainder is 5. If k is less than 40, what is the remainder when k is divided by 7?

A. 2
B. 3
C. 4
D. 5
E. 6



OA B

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Re: When positive integer k is divided by 5, the remainder is 2. When k is divided by 6, the remainder is 5. If k is les

by Brent@GMATPrepNow » Sat Jun 12, 2021 5:01 am
BTGmoderatorDC wrote: ↑
Fri Jun 11, 2021 7:58 pm
 When positive integer k is divided by 5, the remainder is 2. When k is divided by 6, the remainder is 5. If k is less than 40, what is the remainder when k is divided by 7?

A. 2
B. 3
C. 4
D. 5
E. 6



OA B

Source: Magoosh
When it comes to remainders, we have a nice rule that says:
If N divided by D leaves remainder R, then the possible values of N are R, R+D, R+2D, R+3D,. . . etc.
For example, if k divided by 5 leaves a remainder of 1, then the possible values of k are: 1, 1+5, 1+(2)(5), 1+(3)(5), 1+(4)(5), . . . etc.

When positive integer k is divided by 5, the remainder is 2
The possible values of k are: 2, 7, 12, 17, 22, 27, 32, 37, 42, . . .

When k is divided by 6, the remainder is 5.
The possible values of k are: 5, 11, 17, 23, 29, 35, 41. . . .

Since 17 is the only number (less than 40) that both lists share, it must be the case that k = 17

What is the remainder when k is divided by 7?
17 divided by 7 = 2 with remainder 3

Answer: B
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