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What number must be added to each of 2, 16, 20, 52 so that the results are in proportion?

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Re: What number must be added to each of 2, 16, 20, 52 so that the results are in proportion?

by Jay@ManhattanReview » Wed May 06, 2020 10:08 pm
Evo23 wrote: ↑
Wed May 06, 2020 5:29 am
 What number must be added to each of 2, 16, 20, 52 so that the results are in proportion?

A 5
B 7
C 10
D 11
E 12
Say the number of x.

Thus, 2 + x, 16 + x, 20 + x, and 52 + x are in proportion.

=> (2 + x)/(16 + x) = (20 + x)/(52 + x)

=> x = 12

The correct answer: E

Hope this helps!

-Jay
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