M7MBA wrote:What is the value of y? $$(1)\ \ \ y^3+2y=y+2y^2$$ $$(1)\ \ \ y^3+2y=y+2y^2$$ $$(2)\ \ \ y^2=y$$ The OA is the option E.
We need to determine the value of y.
Statement One Alone:
y^3 + 2y = y + 2y^2
y^3 - 2y^2 + y = 0
y(y^2 - 2y + 1) = 0
y(y - 1)(y - 1) = 0
So, y = 0 or y = 1
Statement one alone is not sufficient to answer the question.
Statement Two Alone:
y^2 = y
Simplifying we have:
y^2 - y = 0
y(y - 1) = 0
y = 0 or y = 1
Statement two alone is not sufficient to answer the question.
Statements One and Two Together:
Using both statements, we still see that y = 0 or y = 1; thus, we cannot determine the value of y.
Answer:
E
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