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what is the value of t?

Expert replies
by uptowngirl92 » Sat Jul 25, 2009 5:57 am
In the figure,if POQ is 90deg.then what is the value of t?
1. The value of r is -root3
2. The y-coordinate of point P is 1
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Source: — Data Sufficiency |

by raghavsarathy » Sat Jul 25, 2009 9:16 am
Statement 1 is insufficient because we are not told that the Y coordinate bisects angle O. Hence the value of T depends on the degree to which the triangle is tilted w.r.t the x axis.


Statement 2 is insufficient as we do not know the value of r.

Combining both statements. Drop a perpendicular to the x axis from P. We will know that the angle mad eby PO with x - axis = tan(x) = 1/sqrt(3)
Angle = 30

Angle made by PO witb Y - axis = 60

Not able to proceed after this. Help !
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by gmat740 » Sat Jul 25, 2009 7:42 pm
Please refer to the fig.

We know tanx = y-c0ordinate/x-c0ordinate

so here we get , 1/sq-rt(3) = tan 30 => x = 30(shown in fig)

now we have been given POQ is 90 and the entire fig is enclosed in a semi-cirle => total angle = 180
so we can find angle QOk = 60

Now again in triangle QOK,

We have tan 60 =sq-rt(3)/1 = y-coordinate/x-coordinate

so y-coordinate =u = sq-rt(3)
x-coordinate = t = 1

So OA => C
Apologizes for my horrible drawing skills :oops:

Hope this Helps.
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by raghavsarathy » Sun Jul 26, 2009 5:35 pm
Hi Karan

In your soln you have considered the value of u 1.

But how did you arrive at that ?

The lines PO and OQ subtend different angles with the X- axis. Hence we cannot consider the y-coordinate of point P and y-coordinate of point Q same.
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by gmat740 » Sun Jul 26, 2009 6:11 pm
raghavsarathy wrote:Hi Karan

In your soln you have considered the value of u 1.

But how did you arrive at that ?

The lines PO and OQ subtend different angles with the X- axis. Hence we cannot consider the y-coordinate of point P and y-coordinate of point Q same.
No, Raghav, I did not assume anything.

Look, the angle QOK = 60
and tan 60 = Y-coordinate/X-coordinate
And tan 60 = sq-rt(3) = sq-rt(3)/1

so we have a simple ratio
and correspondingly, sq-rt(3) = Y-cordinate
and 1 = X-cordinate

Hope this helps
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by raghavsarathy » Mon Jul 27, 2009 8:22 am
gmat740 wrote:
and tan 60 = Y-coordinate/X-coordinate
And tan 60 = sq-rt(3) = sq-rt(3)/1
Hi Karan
Sorry to ge this topic again.. How do you know that the value of X-coordinate is 1 (The highlighted part)? It is not mentioned anywhere.
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by gmat740 » Mon Jul 27, 2009 5:42 pm
raghavsarathy wrote:
gmat740 wrote:
and tan 60 = Y-coordinate/X-coordinate
And tan 60 = sq-rt(3) = sq-rt(3)/1
Hi Karan
Sorry to ge this topic again.. How do you know that the value of X-coordinate is 1 (The highlighted part)? It is not mentioned anywhere.
It is a simple ratio. So if the denominator is 1(X-coordinate), then the numerator will be sq-rt(3)

However, since it is a ration, can always say that X-coordinate(denominator) can be 2. I would agree to that, only if the numerator becomes 2 times sq-rt(3). Becoz we have to keep the ratio of Numerator/denominator = Sq-rt(3)

I took the simple ratio and got 1= denominator.

lets say that there are two answers given which are x=1 and x=2, so now which one would you choose??

If you look P(r,s).The distance between P and O(center) = 2(there is formula for calculating distance between 2 points whose whose coordinates are given, I am not going into that detail)

distance between P and O(center) is actually radius.So the max value of x-coordinate on the positive X side(Q-side) will be 2.
However, when X=2, Y-coordinate =0.

But we know the simple ratio has to be sq-rt(3). So definitely x=2 is not the answer.

Hope this long post clears all your doubts
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by pandeyvineet24 » Tue Jul 28, 2009 11:48 am
I think the Answer is D.

Both the statements are providing similar information. One provides the X corodinate of point P and other statement describes the Y coordinate of point P.

in both cases we can determine angle QOK as 60 degrees and the semicircle with a radius of 2.
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by yogami » Wed Jul 29, 2009 11:32 pm
I think the question is messed up. How do you guys assume that that is a semi-circle? If it was given that it was a semi circle then C is correct otherwise its E
200 or 800. It don't matter no more.
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ans

by vyomb » Thu Jul 30, 2009 2:48 am
my answer is C.

Pls confirm the OA.
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by gmat740 » Thu Jul 30, 2009 6:55 am
pandeyvineet24 wrote:I think the Answer is D.

Both the statements are providing similar information. One provides the X corodinate of point P and other statement describes the Y coordinate of point P.

in both cases we can determine angle QOK as 60 degrees and the semicircle with a radius of 2.
I would love to know how will you get the same info using one of the statement.I would be glad to see the working. :D
I think the question is messed up. How do you guys assume that that is a semi-circle? If it was given that it was a semi circle then C is correct otherwise its E
Question is not at all messed up. In the figure It is clear that it is semi-circle.
On GMAT DAY if you find a closed fig. made with 3 closed lines and you say that the question never says anything,these 3 lines could make a Square :shock:

Then you will find your Quant score Very very High!

There are certain minor things which you have to assume by looking at the fig. and this is a semi-circle, you have to assume(untill and unless it doesnt look like a circle! :) )
my answer is C.

Pls confirm the OA.
I am not the poster of this question but still I would say the OA is C. This is a GMAT prep Question.

Hope this Helps
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by pandeyvineet24 » Thu Jul 30, 2009 12:15 pm
gmat740 wrote:
pandeyvineet24 wrote:I think the Answer is D.

Both the statements are providing similar information. One provides the X corodinate of point P and other statement describes the Y coordinate of point P.

in both cases we can determine angle QOK as 60 degrees and the semicircle with a radius of 2.
I would love to know how will you get the same info using one of the statement.I would be glad to see the working. :D

Karan, i know where i messed it up. The answer should be C. I assumed something which i should not have. my bad :shock:
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