What is the surface area of the solid right circular...

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AAPL: Moderator; Posts: 2695; Joined: Sun Oct 29, 2017 2:08 pmFollowed by: 2 members

by AAPL » Wed Nov 22, 2017 2:49 pm

What is the surface area of the solid right circular cylinder with height 10 above?

A. 18Ï€
B. 32Ï€
C. 60Ï€
D. 78Ï€
E. 90Ï€

The OA is D

Please, can any expert assist me with this PS question? I don't have it clear and I appreciate if any explain it for me. Thanks.

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Source: Beat The GMAT — Problem Solving | Wed Nov 22, 2017 2:49 pm

gillissm11: Newbie | Next Rank: 10 Posts; Posts: 2; Joined: Wed Nov 22, 2017 9:14 am; Thanked: 1 times

by gillissm11 » Thu Nov 23, 2017 1:45 am

A=2Ï€rh+2Ï€r2

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EconomistGMATTutor: GMAT Instructor; Posts: 555; Joined: Wed Oct 04, 2017 4:18 pmFollowed by: 12 members; Thanked: 180 times

by EconomistGMATTutor » Thu Nov 23, 2017 11:43 am

What is the surface area of the solid right circular cylinder with height 10 above?

A. 18Ï€
B. 32Ï€
C. 60Ï€
D. 78Ï€
E. 90Ï€

The OA is D

Please, can any expert assist me with this PS question? I don't have it clear and I appreciate if any explain it for me. Thanks.

Hi AAPL,
Let's take a look at your question.
$$Radius=r=3$$
$$Height=h=10$$

We know that the surface area of right circular cylinder can be calculated using the formula:
$$=2\pi r\left(r+h\right)$$
$$=2\pi\left(3\right)\left(3+10\right)$$
$$=6\pi\left(13\right)$$
$$=78\pi$$

Therefore, Option D is correct.

Hope it helps.
I am available of you'd like any follow up.

GMAT Prep From The Economist
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Scott@TargetTestPrep: GMAT Instructor; Posts: 8198; Joined: Sat Apr 25, 2015 10:56 amFollowed by: 29 members; Location: Los Angeles, CA; Thanked: 43 times

by Scott@TargetTestPrep » Sun Oct 13, 2019 5:10 pm

AAPL wrote:

What is the surface area of the solid right circular cylinder with height 10 above?

A. 18Ï€
B. 32Ï€
C. 60Ï€
D. 78Ï€
E. 90Ï€

The OA is D

Please, can any expert assist me with this PS question? I don't have it clear and I appreciate if any explain it for me. Thanks.

The surface area of the cylinder is:

SA = 2Ï€r^2 + 2Ï€rh

SA = 2Ï€(3)^2 + 2Ï€ * 3 * 10

SA = 18Ï€ + 60Ï€ = 78Ï€

Answer: D

Scott Woodbury-Stewart
Founder and CEO
[email protected]

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